UPD78F1502AGK-GAK-AX Datasheet, PDF (902/1031 Pages) Renesas Technology Corp – 16-Bit Single-Chip Microcontrollers

78K0R/Lx3
CHAPTER 31 ELECTRICAL SPECIFICATIONS
DC Characteristics (2/11)
(TA = −40 to +85°C, 1.8 V ≤ VDD = EVDD ≤ 5.5 V, 1.8 V ≤ AVDD0 ≤ VDD,
1.8 V ≤ AVDD ≤ VDD, 1.8 V ≤ EVDD1 = VDD, VSS = EVSS = AVSS = 0 V)
1.8 V ≤ AVDD1 ≤ VDD,
Items
Symbol
Conditions
MIN. TYP. MAX. Unit
Output current, IOL1
low^{Note 1}
Per pin for P00 to P02, P12, P13,
P16, P17, P30 to P34, P40, P41,
P70 to P77, P80 to P87, P120, P130
4.0 V ≤ VDD ≤ 5.5 V
2.7 V ≤ VDD < 4.0 V
1.8 V ≤ VDD < 2.7 V
8.5
mA
1.0
mA
0.5
mA
Per pin for P10, P11, P14, P15
4.0 V ≤ VDD ≤ 5.5 V
8.5
mA
2.7 V ≤ VDD < 4.0 V
1.5
mA
1.8 V ≤ VDD < 2.7 V
0.6
mA
Per pin for P60, P61
4.0 V ≤ VDD ≤ 5.5 V
15.0
mA
2.7 V ≤ VDD < 4.0 V
3.0
mA
1.8 V ≤ VDD < 2.7 V
2.0
mA
Per pin for P50 to P57, P90 to P97,
P100 to P102, P140 to P147
4.0 V ≤ VDD ≤ 5.5 V
2.7 V ≤ VDD < 4.0 V
1.8
mA
0.8
mA
1.8 V ≤ VDD < 2.7 V
0.35
mA
Total of P00 to P02, P10 to P17,
P30 to P34, P40, P41, P70 to P77,
P80 to P87, P120, P130
(When duty = 70% ^{Note 2})
4.0 V ≤ VDD ≤ 5.5 V
2.7 V ≤ VDD < 4.0 V
1.8 V ≤ VDD < 2.7 V
20.0
mA
15.0
mA
9.0
mA
Total of P60, P61
(When duty = 70% ^{Note 2})
4.0 V ≤ VDD ≤ 5.5 V
2.7 V ≤ VDD < 4.0 V
30.0
mA
6.0
mA
1.8 V ≤ VDD < 2.7 V
4.0
mA
Total of P50 to P57, P90 to P97,
P100 to P102, P140 to P147
(When duty = 70% ^{Note 2})
4.0 V ≤ VDD ≤ 5.5 V
2.7 V ≤ VDD < 4.0 V
1.8 V ≤ VDD < 2.7 V
14.4
mA
6.4
mA
2.8
mA
Total of all pins
(When duty = 70% ^{Note 2})
4.0 V ≤ VDD ≤ 5.5 V
2.7 V ≤ VDD < 4.0 V
64.4
mA
27.4
mA
1.8 V ≤ VDD < 2.7 V
15.8
mA
IOL2
Per pin for P20 to P27, P150 to P152, P157
0.4
mA
Per pin for P110, P111
0.4
mA
Notes 1.
2.
Value of current at which the device operation is guaranteed even if the current flows from an output pin to
VSS and AVSS pin.
Specification under conditions where the duty factor is 60% or 70%.
The output current value that has changed the duty ratio can be calculated with the following expression
(when changing the duty factor from 70% to n%).
•Total output current of pins = (IOL × 0.7)/(n × 0.01)
<Example> Where n = 50% and IOL = 20.0 mA
Total output current of pins = (20.0 × 0.7)/(50 × 0.01) = 28.0 mA
However, the current that is allowed to flow into one pin does not vary depending on the duty factor. A
current higher than the absolute maximum rating must not flow into one pin.
Remark Unless specified otherwise, the characteristics of alternate-function pins are the same as those of port pins.
R01UH0004EJ0501 Rev.5.01
886
Jun 20, 2011