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THS3217 Datasheet, PDF (32/73 Pages) Texas Instruments – THS3217 DC to 800-MHz, Differential-to-Single-Ended, DAC Output Amplifier
THS3217
SBOS766B – FEBRUARY 2016 – REVISED FEBRUARY 2016
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Feature Description (continued)
The IN+ buffer output drives a 150-Ω load with VREF grounded. Any source driving VREF must have the ability
to drive a 150-Ω load with low output impedance across frequency. For differential input signals, the IN– buffer
drives a 150-Ω active load. The active load is realized by a combination of the 250-Ω RG resistor and the inverted
and attenuated signal present at the inverting terminal of the difference amplifier stage. If only IN– is driven (with
IN+ at a dc fixed level), the load is 250 Ω.
The resistor values around the D2S difference amplifier are derived in the following sequence, as shown in
Figure 77:
1. Select the feedback resistor value to set the response shape for the wideband CFA stage. The 500-Ω design
used here was chosen as a compromise between loading and noise constraints.
2. Set the input resistor on the inverting input side to give the desired single-sided gain for that path. Setting
RG= 250-Ω results in a gain of –2 V/V from the buffered signal (–V) to the output of the difference amplifier.
3. Solve the required attenuation to the noninverting input to get a matched gain magnitude for the signal
provided at the buffer output (+V) on the noninverting path. If α = R2 / (R1 + R2), as shown in Figure 77,
then the solution for α is shown in Equation 2:
§
D ¨1
RF
·
¸
2
© RG ¹
(1)
D2
R1
3 R1 R2
(2)
RG
250
-V
RF
500
.Â(+V)
VO1
+
R1
+V
R2
Figure 77. D2S Impedance Analysis
4. After solving the attenuation from the buffer output to the amplifier noninverting input, set the impedance (R1
+ R2). It is preferable to have the two first stage buffer outputs drive the same load impedance to match
nonlinearity in their outputs in order to improve even-order harmonic distortion. The load impedance from –V
to RG has an active impedance because of the inverted and attenuated version of the input signal appearing
at the inverting amplifier node from the +V input signal. Assuming a positive input signal into the +V path, an
attenuated version of the signal appears at the amplifier summing junction side of RG, while the inverted
version of the signal appears on the input side of RG.
The impedance seen at node –V in Figure 77 is derived in Equation 3 by solving for the V/I expression across
RG.
Zi
RG
1D
250
12
150
3
(3)
For load balancing, (R1 + R2) = 150 Ω while the attenuation is α. More generally, all the terms are now available
to solve for R2, as shown in Equation 4:
2
R2
RG
D
D1
250 3
12
3
(4)
R1 is then simply (Zi- R2) = 50 Ω.
32
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