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ISL6308 Datasheet, PDF (22/27 Pages) Intersil Corporation – Three-Phase Buck PWM Controller with High Current Integrated MOSFET Drivers
ISL6308
C2
COMP
R2
C1
-
FB
E/A +
VREF
R3
C3
R1
VDIFF
-
RGND
+
VSEN
PWM
CIRCUIT
OSCILLATOR
VOSC
HALF-BRIDGE
DRIVE
VOUT
VIN
UGATE
PHASE
LGATE
L
DCR
C
ESR
ISL6308 EXTERNAL CIRCUIT
FIGURE 21. VOLTAGE-MODE BUCK CONVERTER
COMPENSATION DESIGN
The modulator transfer function is the small-signal transfer
function of VOUT/VCOMP. This function is dominated by a DC
gain, given by dMAXVIN/VOSC, and shaped by the output
filter, with a double pole break frequency at FLC and a zero at
FCE. For the purpose of this analysis, L and DCR represent
the individual channel inductance and its DCR divided by 3
(equivalent parallel value of the three output inductors), while
C and ESR represents the total output capacitance and its
equivalent series resistance.
FLC=
-------------1--------------
2π ⋅ L ⋅ C
FCE=
----------------1-----------------
2π ⋅ C ⋅ ESR
The compensation network consists of the error amplifier
(internal to the ISL6308) and the external R1-R3, C1-C3
components. The goal of the compensation network is to
provide a closed loop transfer function with high 0dB crossing
frequency (F0; typically 0.1 to 0.3 of FSW) and adequate phase
margin (better than 45 degrees). Phase margin is the difference
between the closed loop phase at F0dB and 180°. The
equations that follow relate the compensation network’s poles,
zeros and gain to the components (R1, R2, R3, C1, C2, and
C3) in Figure 20 and 21. Use the following guidelines for
locating the poles and zeros of the compensation network:
1. Select a value for R1 (1kΩ to 5kΩ, typically). Calculate
value for R2 for desired converter bandwidth (F0).
R2
=
---V-----O----S----C-----⋅---R-----1----⋅---F----0-----
dMAX ⋅ VIN ⋅ FLC
If setting the output voltage to be equal to the reference
set voltage as shown in Figure 21, the design procedure
can be followed as presented. However, when setting the
output voltage via a resistor divider placed at the input of
the differential amplifier (as shown in Figure 6), in order
to compensate for the attenuation introduced by the
resistor divider, the obtained R2 value needs be
multiplied by a factor of (RP+RS)/RP. The remainder of
the calculations remain unchanged, as long as the
compensated R2 value is used.
2. Calculate C1 such that FZ1 is placed at a fraction of the FLC,
at 0.1 to 0.75 of FLC (to adjust, change the 0.5 factor to
desired number). The higher the quality factor of the output
filter and/or the higher the ratio FCE/FLC, the lower the FZ1
frequency (to maximize phase boost at FLC).
C1
=
-----------------------1-----------------------
2π ⋅ R2 ⋅ 0.5 ⋅ FLC
3. Calculate C2 such that FP1 is placed at FCE.
C2 = -2---π-----⋅---R-----2----⋅---C-C----1-1---⋅---F----C----E-----–-----1-
4. Calculate R3 such that FZ2 is placed at FLC. Calculate C3
such that FP2 is placed below FSW (typically, 0.5 to 1.0
times FSW). FSW represents the per-channel switching
frequency. Change the numerical factor to reflect desired
placement of this pole. Placement of FP2 lower in
frequency helps reduce the gain of the compensation
network at high frequency, in turn reducing the HF ripple
component at the COMP pin and minimizing resultant
duty cycle jitter.
R3
=
--------R-----1--------
F----S----W---- – 1
FLC
C3
=
-----------------------1-------------------------
2π ⋅ R3 ⋅ 0.7 ⋅ FSW
It is recommended a mathematical model is used to plot the
loop response. Check the loop gain against the error
amplifier’s open-loop gain. Verify phase margin results and
adjust as necessary. The following equations describe the
frequency response of the modulator (GMOD), feedback
compensation (GFB) and closed-loop response (GCL):
GMOD(f)
=
-d---M-----A----X-----⋅---V----I--N--
VOSC
⋅
-------------------------------1-----+-----s---(---f--)---⋅---E-----S----R------⋅---C----------------------------------
1 + s(f) ⋅ (ESR + DCR) ⋅ C + s2(f) ⋅ L ⋅ C
GFB(f) = -s---(-1-f---)-+--⋅---sR---(--1-f--)-⋅--⋅-(--RC-----21----⋅+---C--C---1--2----) ⋅
⋅ ------------------------------1-----+-----s---(---f--)---⋅---(---R----1-----+-----R----3----)---⋅---C-----3-------------------------------
(1
+
s
(
f
)
⋅
R3
⋅
C3
)
⋅

1

+
s
(
f
)
⋅
R2
⋅



C-C----1-1----+-⋅--C-C----2-2-



GCL(f) = GMOD(f) ⋅ GFB(f) where, s(f) = 2π ⋅ f ⋅ j
22
FN9208.2
October 19, 2005