THS6032_14 Datasheet, PDF (8/35 Pages) Texas Instruments – LOW-POWER ADSL CENTRAL-OFFICE LINE DRIVER

THS6032
SLOS233F – APRIL 1999 – REVISED AUGUST 2009....................................................................................................................................................... www.ti.com
TYPICAL CHARACTERISTICS
OUTPUT AMPLITUDE
vs
FREQUENCY
2
1
R_F = 1 kΩ
R_F = 1.3 kΩ
0
−1
−2
R_F = 1.5 kΩ
−3
−4
V_CC(H) = ± 15 V
−5
V_CC(L) = ± 5 V
Gain = +1
−6 RL = 25 Ω
V_O = 0.2 V_RMS
−7
100 k
1M
10 M
100 M
f − Frequency − Hz
500 M
Figure 1.
OUTPUT AMPLITUDE
vs
FREQUENCY
0.4
0.3
0.2
0.1
−0.0
V_CC(H) = ± 15 V
V_CC(L) = ± 5 V
Gain = +1
R_L = 25 Ω
V_O = 0.2 V_RMS
R_F = 1 kΩ
−0.1
−0.2
R_F = 1.3 kΩ
−0.3
−0.4
100 k
R_F = 1.5 kΩ
1M
10 M
100 M 500 M
f − Frequency − Hz
Figure 2.
OUTPUT AMPLITUDE
vs
FREQUENCY
8
7
R_F = 820 Ω
6
R_F = 1.1 kΩ
5
4
R_F = 1.3 kΩ
3
2
V_CC(H) = ± 15 V
1
V_CC(L) = ± 5 V
Gain = +2
0 RL = 25 Ω
V_O = 0.4 V_RMS
−1
100 k
1M
10 M
100 M
f − Frequency − Hz
500 M
Figure 3.
OUTPUT AMPLITUDE
vs
FREQUENCY
6.4
V_CC(H) = ± 15 V
6.3 V_CC(L) = ± 5 V
Gain = +2
6.2 R_L = 25 Ω
V_O = 0.4 V_RMS
6.1
R_F = 820 Ω
6.0
5.9
R_F = 1.1 kΩ
5.8
5.7
R_F = 1.3 kΩ
5.6
100 k
1M
10 M
100 M 500 M
f − Frequency − Hz
Figure 4.
OUTPUT AMPLITUDE
vs
FREQUENCY
16
15
R_F = 330 Ω
14
13
R_F = 820 Ω
12
R_F = 1.5 kΩ
11
10
V_CC(H) = ± 15 V
9
V_CC(L) = ± 5 V
Gain = +5
8 ^RL^{= 25 Ω}
V_O = 0.2 V_RMS
7
100k
1M
10M
f − Frequency − Hz
100M
500M
Figure 5.
OUTPUT AMPLITUDE
vs
FREQUENCY
22
21
R_F = 510 Ω
20
19
18
R_F = 1 kΩ
17
16
V_CC(H) = ± 15 V
V_CC(L) = ± 5 V
15
Gain = +10
14
R_L= 25 Ω
V_O = 0.2 V_RMS
13
100k
1M
10M
100M 500M
f − Frequency − Hz
Figure 6.
CLASS-AB MODE OUTPUT AMPLITUDE
vs
FREQUENCY
8
6
Gain = +2
4 R_F =1.1 kΩ
2
V_CC(H) = ± 15 V
V_CC(L) = GND
0
Gain = +1
−2 RF =1.3 kΩ
−4
−6
100 k
R_L = 25 Ω
V_I = 0.2 V_RMS
1M
10 M
100 M 500 M
f − Frequency − Hz
Figure 7.
OUTPUT AMPLITUDE
vs
FREQUENCY
8
Gain = +2, R_F = 1.1 kΩ
6
4
2
Gain = +1, R_F = 1.3 kΩ
0
−2
−4 V_CC(H) = ± 15 V
V_CC(L) = ± 5 V
−6 _{RL = 100 Ω}
V_I = 0.2 V_RMS
−8
100 k
1M
10 M
100 M
f − Frequency − Hz
500 M
Figure 8.
SMALL AND LARGE SIGNAL
FREQUENCY RESPONSE
18
V_O(PP) = 4 V
12
V_CC(H) = ± 15 V
V_CC(L) = ± 5 V
V_O(PP) = 2 V
6
0
V_O(PP) = 1 V
−6
V_O(PP) = 0.5 V
V_O(PP) = 0.25 V
−12
Gain = +1
−18 ^{RL = 25 Ω RF = 1.3 k Ω}
100 k
1M
10 M
100 M
f − Frequency − Hz
500 M
Figure 9.
8
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