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THS3202_16 Datasheet, PDF (8/37 Pages) Texas Instruments – 2-GHz, LOW DISTORTION, DUAL CURRENT-FEEDBACK AMPLIFIERS
THS3202
SLOS242F – SEPTEMBER 2002 – REVISED JANUARY 2010
SMALL-SIGNAL FREQUENCY
RESPONSE
44
33
Rf = 500 Ω
22
11
00
−−11
Rf = 619 Ω
−−22
G=1
−−33 RL = 100 Ω
−−44
VCC = ±5 V
VO = 100 mVPP
−−55
0.1 M 1 M 10 M 100 M 1 G
10G
f − Frequency − Hz
Figure 1.
TYPICAL CHARACTERISTICS
SMALL-SIGNAL FREQUENCY
RESPONSE
3
2
Rf = 500 Ω
1
0
−1
Rf = 619 Ω
−2
−3 G = 1
RL = 100 Ω
−4 VCC = 15 V
VO = 100 mVPP
−5
0.1 M 1 M 10 M 100 M 1 G
f − Frequency − Hz
Figure 2.
10 G
SMALL-SIGNAL FREQUENCY
RESPONSE
9
8
Rf = 402 Ω
7
6
5
Rf = 536 Ω
4
3
Rf = 650 Ω
2 G=2
RL = 100 Ω
1 VCC = 15 V
VO = 100 mVPP
0
0.1 M 1 M 10 M 100 M 1 G
f − Frequency − Hz
10 G
Figure 4.
SMALL-SIGNAL FREQUENCY
RESPONSE
9
8
Rf = 402 Ω
7
6
5
Rf = 536 Ω
4
3
Rf = 650 Ω
2 G=2
RL = 100 Ω
1 VCC = ±5 V
VO = 100 mVPP
0
0.1 M 1 M 10 M 100 M 1 G
f − Frequency − Hz
10 G
Figure 5.
SMALL-SIGNAL FREQUENCY
RESPONSE
9
8
7
Rf = 536 Ω
6
5
4
Rf = 649 Ω
3
2 G=2
RL = 500 Ω
1 VCC = ±5 V
VO = 100 mVPP
0
0.1 M 1 M 10 M 100 M 1 G
f − Frequency − Hz
10 G
Figure 7.
SMALL-SIGNAL FREQUENCY
RESPONSE
16
Rf = 300 Ω
15
14
13
Rf = 402 Ω
12
G=5
Rf = 500 Ω
11 RL = 100 Ω
VCC = 15 V
VO = 100 mVPP
10
0.1 M 1 M 10 M 100 M 1 G
f − Frequency − Hz
Figure 8.
10 G
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SMALL-SIGNAL FREQUENCY
RESPONSE
6
5 G=1
RL = 500 Ω
4 VCC = ±5 V
3 VO = 100 mVPP
2
1
Rf = 619 Ω
0
−1
−2
Rf = 750 Ω
−3
−4
0.1 M
1 M 10 M 100 M 1 G
f − Frequency − Hz
10 G
Figure 3.
SMALL-SIGNAL FREQUENCY
RESPONSE
12
G=2
11 RL = 500 Ω
10 VCC = 15 V
9 VO = 100 mVPP
8
Rf = 536 Ω
7
6
5
4
Rf = 649 Ω
3
2
1
0
0.1 M
1 M 10 M 100 M 1 G
f − Frequency − Hz
10 G
Figure 6.
SMALL-SIGNAL FREQUENCY
RESPONSE
16
15
Rf = 300 Ω
14
13
Rf = 402 Ω
12
11
Rf = 500 Ω
10 G = 5
RL = 100 Ω
9 VCC = ±5 V
VO = 100 mVPP
8
0.1 M 1 M 10 M 100 M 1 G
f − Frequency − Hz
Figure 9.
10 G
8
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