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LTC3114-1_15 Datasheet, PDF (26/34 Pages) Linear Technology – 40V, 1A Synchronous Buck-Boost DC/DC Converter with Programmable Output Current
LTC3114-1
APPLICATIONS INFORMATION
where:
GCS is the inner current loop closed-loop transconduc-
tance = 1.97A/V
RLOAD is the minimum load resistance in ohms
gm is the transconductance of the error amplifier, 120µS
RZ is the compensation zero setting resistor (one of
our design variables)
VOUT is the output voltage
Our desired closed-loop frequency (fCC) defined earlier is
29kHz. Assuming that we have a single pole response in
our system, we can express the ratio of the closed-loop
crossover frequency to fP1 in the buck mode of operation
as follows:
fCC = GCS •RLOAD • gm •Rz
fP1
VO
We can now calculate RZ by rearranging the previous
equation:
RZ
=
fCC
•
VOUT • 2π •COUT
GCS • gm
It’s important to note that the value of RZ is proportional
to the overall crossover frequency, fCC. If we later want to
adjust fCC lower, for example, RZ can be lowered in value
and CP1 increased proportionally to keep the compensa-
tion zero at the same frequency.
As mentioned previously, we will place the zero at fre-
quency P1, yielding:
CP1
=
2π
1
•RZ
•
fP1
or more simply,
RLOAD • COUT
RZ
where Rl is the minimum load resistance in buck mode,
12Ω in this example.
Quickly substituting our values in the above equations
yields:
RZ = 407k, CP1 = 1.3nF,
but please continue reading as this is not the final answer.
If the inner current loop were an ideal VCCS, then the
previously derived compensation would be sufficient to
stabilize the converter. However, the inner current loop
utilizes an operational amplifier with an integral compen-
sation network, which contributes an additional zero and
pole in the power stage response, the gain peaking, as
described previously. The effect of the additional zero/pole
pair pushes out fCC, our crossover frequency, beyond what
was predicted by the previous calculations. A simplified
approach to calculating our compensation components
then is to re-use the previous equations but scale fCC, the
cross over frequency, by a scaling factor (α), which will
account for the gain boost present in the system:
fCC′
=
fCC
3
•(α),
where
α
=
0.42
So, in our example, this results in:
fCC′
=
29kHz
3
•
(0.42)
=
4.06kHz
Using the new value of fCC′ in the previous equations for
RZ and CC yields:
RZ
=
4.06kHz•12V • 2π • 44µF
1.97A • 120µA
V
V
RZ = 56.9kΩ, use 56.2kΩ
CP1
=
12Ω • 44µF
56.2k
CP1 = 9.4nF, use 10nF
CP2 is usually chosen to be a small value around 10pF as
it is meant to filter out high frequency switching frequency
related components.
Keep in mind that this analysis assumes that the zero pro-
vided by the output capacitor and its ESR is at a frequency
much higher than fCC.
26
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