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LTC3720_15 Datasheet, PDF (18/24 Pages) Linear Technology – Single Phase VRM8.5 Current Mode Step-Down Controller
LTC3720
APPLICATIO S I FOR ATIO
Design Example
As a design example, take a supply with the following
specifications: VIN = 7V to 24V (15V nominal), VOUT = 1.05V
to 1.825V with typical at 1.5V, IOUT(MAX) = 15A, f = 300kHz.
First, calculate the timing resistor with VON = VOUT:
( )( ) RON =
1
= 330k
300kHz 10pF
and choose the inductor for about 40% ripple current at
the maximum VIN:
( )( )( ) L =
1.5V
300kHz 0.4
15A

1−
1.5V 
24V 
=
0.8µH
Selecting a standard value of 1µH results in a maximum
ripple current of:
( )( ) ∆IL =
1.5V
300kHz 1µH

1–
1.5V 
24V 
=
4.7A
Next, choose the synchronous MOSFET switch. Because
of the narrow duty cycle and large current, a single SO-8
MOSFET will have difficulty dissipating the power lost in the
switch. Choosing two IRF7811A (RDS(ON) = 0.013Ω, CRSS
= 60pF, θJA = 50°C/W) yields a nominal sense voltage of:
VSNS(NOM) = (15A)(0.5)(1.3)(0.012Ω) = 117mV
Tying VRNG to INTVCC will set the current sense voltage
range for a nominal value of 140mV with current limit
occurring at 186mV. To check if the current limit is
acceptable, assume a junction temperature of about 100°C
above a 50°C ambient with ρ150°C = 1.6:
( )( )( ) ( ) ILIMIT ≥
0.5
186mV
1.6 0.012Ω
+ 1 4.7A
2
= 18A
and double check the assumed TJ in the MOSFET:
( )( ) PBOT
=
24V – 1.5V  21.7A 2
24V  2 
1.6
0.012Ω
= 2.12W
TJ = 50°C + (2.12W)(50°C/W) = 156°C
Because the top MOSFET is on for such a short time, a
single IRF7811A will be sufficient. Checking its power
dissipation at current limit with ρ90°C = 1.3:
( ) ( )( ) PBOT
=
1.5V
24V
2
21.7A 1.3
0.012Ω
+
(1.7)(24V)2( )( 21.7A 60pF)(300kHz)
= 0.46W + 0.38W = 0.84W
TJ = 50°C + (0.84W)(50°C/W) = 92°C
The junction temperatures will be significantly less at
nominal current, but this analysis shows that careful
attention to heat sinking will be necessary in this circuit.
CIN is chosen for an RMS current rating of about 6A at
temperature. The output capacitors are chosen for a low
ESR of 0.005Ω to minimize output voltage changes due to
inductor ripple current and load steps. The ripple voltage
will be only:
∆VOUT(RIPPLE) = ∆IL(MAX) (ESR)
= (4.7A) (0.005Ω) = 24mV
3720f
18