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ISL6252 Datasheet, PDF (21/25 Pages) Intersil Corporation – Highly Integrated Battery Charger Controller for Notebook Computers
ISL6252, ISL6252A
20
10
0
-10
-20
-30 RBATTERY = 200mΩ
-40
-50
RBATTERY = 50mΩ
-60
NO BATTERY
-20
-40
-60
-80
-100
-120
-140
-160
100 200 500 1k 2k 5k 10k 20k 50k 100k 200k 500k
FREQUENCY
FIGURE 23. FREQUENCY RESPONSE OF THE LC OUTPUT
The resistanceFILRTOEiRs a combination of MOSFET rDS(ON),
inductor DCR, RSENSE and the internal resistance of the
battery (normally between 50mΩ and 200mΩ). The worst
case for voltage mode control is when the battery is absent.
This results in the highest Q of the LC filter and the lowest
phase margin.
The compensation network consists of the voltage error
amplifier gm1 and the compensation network RVCOMP,
CVCOMP, which give the loop very high DC gain, a very low
frequency pole and a zero at fZERO1. Inductor current
information is added to the feedback to create a second
zero, fZERO2. The low pass filter RF2, CF2 between RSENSE
and ISL6252 add a pole at fFILTER. R3 and R4 are internal
divider resistors that set the DC output voltage. For a 3-cell
battery, R3 = 320kΩ and R4 = 64kΩ. Equations 37, 38, 39,
40, 41 and 42 relate the compensation network’s poles,
zeros and gain to the components in Figure 22. Figure 24
shows an asymptotic Bode plot of the DC/DC converter’s
gain vs frequency. It is strongly recommended that fZERO1 is
approximately 30% of fLC and fZERO2 is approximately 70%
of fLC.
COMPENSATOR
MODULATOR
fLC
fPOLE1
40
LOOP
20
0
-20
fFILTER
-40
fZERO1
fZERO2
FESR
-60
0.1k
1k
10k
100k
1M
FREQUENCY (Hz)
FIGURE 24. ASYMPTOTIC BODE PLOT OF THE VOLTAGE
CONTROL LOOP GAIN
COMPENSATION BREAK FREQUENCY EQUATIONS
fZERO1
=
----------------------------------1------------------------------------
(2π ⋅ CVCOMP ⋅ R1COMP)
(EQ. 37)
fZERO2
=
⎛
⎜
⎝
-2---π-----⋅---R----R-S----EV---N-C----SO----EM-----⋅P---C----O-----U----T- ⎠⎟⎞
⋅
⎛
⎜
⎝
R-----4--R--+---4--R-----3-⎠⎟⎞
⋅ ⎝⎛g----m-5-----1--⎠⎞
(EQ. 38)
fLC
=
---------------1----------------
(2π L ⋅ Co)
fFILTER
=
--------------------1----------------------
(2π ⋅ RF2 ⋅ CF2)
fPOLE1 = (---2----π-----⋅---R----S----E--1--N----S----E-----⋅---C-----o---)
fESR
=
---------------------1-----------------------
(2π ⋅ Co ⋅ RESR)
(EQ. 39)
(EQ. 40)
(EQ. 41)
(EQ. 42)
21
FN6498.3
August 25, 2010