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ISL6446IAZ-TK Datasheet, PDF (16/19 Pages) Intersil Corporation – Dual (180° Out-of-Phase) PWM and Linear Controller
ISL6446
C2
COMP
R2 C1
-
FB
E/A +
VREF
R3 C3
R1
Ro
OSCILLATOR
PWM
CIRCUIT
VOSC
HALF-BRIDGE
DRIVE
VIN
L
UGATE
PHASE
LGATE
VOUT
D
C
E
ISL6446 EXTERNAL CIRCUIT
FIGURE 26. VOLTAGE-MODE BUCK CONVERTER COMPENSATION
DESIGN
FLC=
-------------1--------------
2π ⋅ L ⋅ C
(EQ. 11)
FCE= 2----π-----⋅--1-C------⋅---E--
(EQ. 12)
The compensation network consists of the error amplifier
(internal to the ISL6446) and the external R1-R3, C1-C3
components. The goal of the compensation network is to provide
a closed loop transfer function with high 0dB crossing frequency
(F0; typically 0.1 to 0.3 of FSW) and adequate phase margin
(better than 45°). Phase margin is the difference between the
closed loop phase at F0dB and 180°. The equations that follow
relate the compensation network’s poles, zeros and gain to the
components (R1 , R2, R3, C1 , C2, and C3) in Figure 26. Use the
following guidelines for locating the poles and zeros of the
compensation network:
1. Select a value for R1 (1kΩ to 5kΩ, typically). Calculate the
value for R2 for desired converter bandwidth (F0). If setting
the output voltage via an offset resistor connected to the FB
pin, Ro in Figure 26, the design procedure can be followed as
presented in Equation 13.
R2
=
---V----O-----S----C-----⋅---R-----1-----⋅---F----0----
dMAX ⋅ VIN ⋅ FLC
(EQ. 13)
2. Calculate C1 such that FZ1 is placed at a fraction of the FLC, at 0.1
to 0.75 of FLC (to adjust, change the 0.5 factor to desired
number). The higher the quality factor of the output filter and/or
the higher the ratio FCE/FLC, the lower the FZ1 frequency (to
maximize phase boost at FLC).
C1
=
-----------------------1------------------------
2π ⋅ R2 ⋅ 0.5 ⋅ FLC
(EQ. 14)
3. Calculate C2 such that FP1 is placed at FCE.
C2
=
-------------------------C-----1---------------------------
2π ⋅ R2 ⋅ C1 ⋅ FCE – 1
(EQ. 15)
4. Calculate R3 such that FZ2 is placed at FLC. Calculate C3 such
that FP2 is placed below FSW (typically, 0.5 to 1.0 times FSW).
FSW represents the switching frequency. Change the
numerical factor to reflect desired placement of this pole.
Placement of FP2 lower in frequency helps reduce the gain of
the compensation network at high frequency, in turn reducing
the HF ripple component at the COMP pin and minimizing
resultant duty cycle jitter.
R3
=
--------R----1---------
F----S----W----
FLC
–
1
C3 = -2---π-----⋅---R-----3-----⋅--1-0---.--7-----⋅---F---S----W----
(EQ. 16)
It is recommended a mathematical model is used to plot the
loop response. Check the loop gain against the error amplifier’s
open-loop gain. Verify phase margin results and adjust as
necessary. The following equations describe the frequency
response of the modulator (GMOD), feedback compensation
(GFB) and closed-loop response (GCL):
GMOD(f)
=
-d---M-----A----X-----⋅---V----I--N--
VOSC
⋅
--------------------------1-----+-----s----(--f--)----⋅---E-----⋅---C-----------------------------
1 + s(f) ⋅ (E + D) ⋅ C + s2(f) ⋅ L ⋅ C
(EQ. 17)
GFB(f)
=
-----1-----+-----s----(--f--)----⋅---R----2-----⋅---C-----1-------
s(f) ⋅ R1 ⋅ (C1 + C2)
⋅
⋅ -------------------------------1-----+-----s---(--f---)---⋅---(--R-----1-----+-----R-----3----)---⋅---C-----3--------------------------------
(1
+
s
(f)
⋅
R
3
⋅
C
3
)
⋅
⎝⎛1
+
s(
f)
⋅
R2
⋅
⎛
⎝
C-C----1-1----+-⋅---C-C----2-2--⎠⎞
⎞
⎠
(EQ. 18)
GCL(f) = GMOD(f) ⋅ GFB(f)
where:
s(f) = 2π ⋅ f ⋅ j
(EQ. 19)
COMPENSATION BREAK FREQUENCY EQUATIONS
FZ1 = 2----π-----⋅---R---1--2-----⋅---C-----1-
(EQ. 20)
FZ2
=
-------------------------1--------------------------
2π ⋅ (R1 + R3) ⋅ C3
(EQ. 21)
FP1
=
----------------------1------------------------
2π ⋅ R2 ⋅ -C-----1-----⋅---C-----2---
C1 + C2
FP2 = 2----π-----⋅---R---1--3-----⋅---C-----3-
(EQ. 22)
(EQ. 23)
16
FN7944.1
October 15, 2013