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MAX16930 Datasheet, PDF (22/29 Pages) Maxim Integrated Products – 2MHz, 36V, Dual Buck with Preboost and 20μA Quiescent Current
MAX16930/MAX16931
2MHz, 36V, Dual Buck with Preboost and
20µA Quiescent Current
At the crossover frequency, the total loop gain must be
equal to 1. So:
GAINMOD(fC )
×
VFB
VOUT
× GAINEA(fC )
= 1
GAINE= A(fC) gm,EA × RC
G= AINMOD(fC )
GAINMOD(dc)
×
fpMOD
fC
fSW = 26.4/65.5kI = 0.403MHz
GAINMOD(dc) =6.06 × 0.9375 =5.68
= fpMOD
1
≈ 1.8kHz
2π × 94µF × 0.9375
fpMOD
<<
fC
≤
fSW
5
1.8kHz << fC ≤ 80.6kHz
Therefore:
select fC = 40kHz
GAINMOD(fC )
× VFB
VOUT
× gm,EA
×RC
= 1
= fzMOD
1
≈ 376kHz
2π × 4.5mΩ × 94µF
Solving for RC:
RC
=
gm,EA
VOUT
× VFB × GAINMOD(fC )
since fzMOD>fC:
RC ≈ 16kI
CC ≈ 5.6nF
CF ≈ 27pF
Set the error-amplifier compensation zero formed by RC
and CC at the fpMOD. Calculate the value of CC as follows:
Boost Converter Design Procedure
Setting the Output Voltage in Boost Converter
Adjust the boost converter output voltage by connecting
CC =
1
2π × fpMOD × RC
a resistive divider from the output of the boost converter
to FBBST to TERM (Figure 3) and RB2 (FB3 to TERM
resistor). Calculate RB1 (VOUT(BOOST) to FBBST resistor)
If fzMOD is less than 5 x fC, add a second capacitor CF
using the following equation:
from COMP to AGND. The value of CF is:
CF =
1
= RB1
R
B2


VOUT (BOOST
VFB3
)


−

1

2π × fzMOD × RC
where VFB3 = 1.2V (typ) (see the Electrical Characteristics
table).
As the load current decreases, the modulator pole also
decreases; however, the modulator gain increases accord-
ingly and the crossover frequency remains the same.
Below is a numerical example to calculate the compen-
VOUT(BOOST)
sation network component values of Figure 2:
AV_CS = 11V/V
MAX16930/
RB1
MAX16931
RDCR = 15mI
FB3
gmc = 1/(AV_CS x RDC) = 1/(11 x 0.015) = 6.06
VOUT = 5V
RB2
IOUT(MAX) = 5.33A
TERM
RLOAD = VOUT/IOUT(MAX) = 5V/5.33A = 0.9375I
COUT = 2x47µF = 94µF
ESR = 9mI/2 = 4.5mI
Figure 3. Boost Converter Adjustable Output Voltage
Maxim Integrated
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