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MAX15039_11 Datasheet, PDF (15/19 Pages) Maxim Integrated Products – 6A, 2MHz Step-Down Regulator with Integrated Switches Open-Drain, Power-Good Output
6A, 2MHz Step-Down Regulator
with Integrated Switches
Compensation Design
The power transfer function consists of one double pole
and one zero. The double pole is introduced by the
inductor L and the output capacitor CO. The ESR of the
output capacitor determines the zero. The double pole
and zero frequencies are given as follows:
fP1_LC = fP2 _LC =
1
2π x
L
x
CO
x
⎛
⎝⎜
RO + ESR
RO + RL
⎞
⎠⎟
fZ _ESR
=
2π
1
x ESR
x
CO
where RL is equal to the sum of the output inductor’s DCR
(DC resistance) and the internal switch resistance,
RDS(ON). A typical value for RDS(ON) is 20mΩ (low-side
MOSFET) and 26mΩ (high-side MOSFET). RO is the output
load resistance, which is equal to the rated output voltage
divided by the rated output current. ESR is the total equiv-
alent series resistance of the output capacitor. If there is
more than one output capacitor of the same type in paral-
lel, the value of the ESR in the above equation is equal to
that of the ESR of a single output capacitor divided by the
total number of output capacitors.
The high switching frequency range of the MAX15039
allows the use of ceramic output capacitors. Since the
ESR of ceramic capacitors is typically very low, the fre-
quency of the associated transfer function zero is higher
than the unity-gain crossover frequency, fC, and the zero
cannot be used to compensate for the double pole creat-
ed by the output filtering inductor and capacitor. The dou-
ble pole produces a gain drop of 40dB/decade and a
phase shift of 180°. The compensation network error
amplifier must compensate for this gain drop and phase
shift to achieve a stable high-bandwidth closed-loop sys-
tem. Therefore, use type III compensation as shown in
Figures 3 and 4. Type III compensation possesses three
poles and two zeros with the first pole, fP1_EA, located at
zero frequency (DC). Locations of other poles and zeros
of the type III compensation are given by:
fZ1_ EA
=
2π
×
1
R1
×
C1
fZ2 _EA
=
2π
×
1
R3
×
C3
fP3 _EA
=
2π
×
1
R1 ×
C2
fP2 _EA
=
2π
×
1
R2
×
C3
The above equations are based on the assumptions
that C1 >> C2 and R3 >> R2 are true in most applica-
tions. Placements of these poles and zeros are deter-
mined by the frequencies of the double pole and ESR
zero of the power transfer function. It is also a function
of the desired close-loop bandwidth. The following sec-
tion outlines the step-by-step design procedure to cal-
culate the required compensation components for the
MAX15039. When the output voltage of the MAX15039
is programmed to a preset voltage, R3 is internal to the
IC and R4 does not exist (Figure 3b).
When externally programming the MAX15039 (Figure
3a), the output voltage is determined by:
R4
=
0.6 × R3
(VOUT − 0.6)
(for
VOUT
>
0.6V)
or:
R4 = (VREFIN × R3)
(VOUT − VREFIN)
if using an external VREFIN, and VOUT > VREFIN.
For a 0.6V output, or for VOUT = VREFIN, connect an
8.06kΩ resistor from FB to VOUT. The zero-cross fre-
quency of the close-loop, fC, should be between 10%
and 20% of the switching frequency, fS. A higher zero-
cross frequency results in faster transient response.
Once fC is chosen, C1 is calculated from the following
equation:
1.5625 x VIN
C1 =
2
x
π
x
R3
x
VP − P
(1+ RL ) ×
RO
fC
where VP-P is the ramp peak-to-peak voltage (1V typ).
Due to the underdamped nature of the output LC dou-
ble pole, set the two zero frequencies of the type III
compensation less than the LC double-pole frequency
to provide adequate phase boost. Set the two zero fre-
quencies to 80% of the LC double-pole frequency.
Hence:
R1 = 1 x L x CO x (RO + ESR)
0.8 x C1
RL + RO
C3 = 1 x L x CO x (RO + ESR)
0.8 x R3
RL + RO
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