English
Language : 

LTC3814-5_15 Datasheet, PDF (24/30 Pages) Linear Technology – 60V Current Mode Synchronous Step-Up Controller
LTC3814-5
APPLICATIONS INFORMATION
about 3mA and driver current can be calculated by:
IGATE = f(QG(TOP) + QG(BOT)), where QG(TOP) and QG(BOT)
are the gate charges of the top and bottom MOSFETs.
This loss is proportional to the supply voltage that
INTVCC is derived from, i.e., VIN, VOUT or an external
supply connected to INTVCC.
4. COUT loss. The output capacitor has the difficult job
of filtering the large RMS input current out of the synchro-
nous MOSFET. It must have a very low ESR to minimize
the AC I2R loss.
Other losses, including CIN ESR loss, Schottky diode D1
conduction loss during dead time and inductor core loss
generally account for less than 2% additional loss. When
making adjustments to improve efficiency, the input cur-
rent is the best indicator of changes in efficiency. If you
make a change and the input current decreases, then the
efficiency has increased. If there is no change in input
current, then there is no change in efficiency.
Checking Transient Response
The regulator loop response can be checked by looking
at the load transient response. Switching regulators take
several cycles to respond to a step in load current. When
load step occurs, VOUT immediately shifts by an amount
equal to ∆ILOAD (ESR), where ESR is the effective series
resistance of COUT. ∆ILOAD also begins to charge or dis-
charge COUT generating a feedback error signal used by the
regulator to return VOUT to its steady-state value. During
this recovery time, VOUT can be monitored for overshoot
or ringing that would indicate a stability problem.
Design Example
As a design example, take a supply with the following speci-
fications: VIN = 12V ±20%, VOUT = 24V ±5%, IOUT(MAX) =
5A, f = 250kHz. Since VIN can vary around the 12V nominal
value, connect a resistive divider from VIN to VOFF to keep
the frequency independent of VIN changes:
R1 = 12V − 1= 6.74
R2 1.55V
Choose R1 = 133k and R2 = 20k. Now calculate timing
resistor ROFF:
ROFF
=
1+ 133k / 20k
250kHz • 76pF
=
402.6k
The duty cycle is:
D = 1− 12V = 0.5
24V
and the maximum input current is:
IIN(MAX
)
=
5A
1− 0.5
=
10A
Choose the inductor for about 40% ripple current at the
maximum VIN:
L
=
12V
250kHz • 0.4
•
10A


1
12V
24V


=
6μH
The peak inductor current is:
IL(PEAK
)
=
5A
1− 0.5
+
1(4A)
2
=
12A
so, choose the CDEP147 5.9μH inductor with ISAT = 16.4A
at 100°C.
Next, choose the bottom MOSFET switch. Since the drain
of the MOSFET will see the full output voltage plus any
ringing, choose a 40V MOSFET to provide a margin of
safety. The Si7848DP has:
BVDSS = 40V
RDS(ON) = 9mΩ(max)/7.5mΩ(nom),
δ = 0.006/°C,
CMILLER = (14nC – 6nC)/20V = 400pF,
VGS(MILLER) = 3.5V,
θJA= 20°C/W.
This yields a nominal sense voltage of:
VSNS(NOM)
=
1.7
•
0.0075Ω
1− 0.5
•
5A
=
128mV
38145fc
24