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LTC3789_15 Datasheet, PDF (23/30 Pages) Linear Technology – High Efficiency, Synchronous, 4-Switch Buck-Boost Controller
LTC3789
APPLICATIONS INFORMATION
Design Example
VIN = 5V to 18V
VOUT = 12V
IOUT(MAX) = 5A
f = 400kHz
Maximum ambient temperature = 60°C
Set the frequency at 400kHz by applying 1.2V on the FREQ
pin (see Figure 7). The 10µA current flowing out of the
FREQ pin will give 1.2V across a 120k resistor to GND. The
inductance value is chosen first based on a 30% ripple cur-
rent assumption. In the buck region, the ripple current is:
∆IL,BUCK
=
VOUT
f •L
•


1
–
VOUT 
VIN 
IRIPPLE,BUCK
=
∆IL,BUCK • 100 %
IOUT
The highest value of ripple current occurs at the maximum
input voltage. In the boost region, the ripple current is:
∆IL,BOOST =
VIN •
f •L


1
–
VIN
VOUT


IRIPPLE,BOOST
=
∆I L,BOOST
I IN
• 100
%
The highest value of ripple current occurs at VIN = VOUT/2.
A 6.8µH inductor will produce 11% ripple in the boost region
(VIN = 6V) and 29% ripple in the buck region (VIN = 18V).
The RSENSE resistor value can be calculated by using the
maximum current sense voltage specification with some
accommodation for tolerances.
RSENSE
=
2
2 • 140mV •
• IOUT(MAX,BOOST) • VOUT
VIN(MIN)
+ ∆IL,BOOST
•
VIN(MIN)
Select an RSENSE of 10mΩ.
Output voltage is 12V. Select R1 as 20k. R2 is:
R2 = VOUT • R1 – R1
0.8
Select R2 as 280k. Both R1 and R2 should have a toler-
ance of no more than 1%.
Selecting MOSFET Switches
The MOSFETs are selected based on voltage rating and
RDS(ON) value. It is important to ensure that the part is
specified for operation with the available gate voltage am-
plitude. In this case, the amplitude is 5.5V and MOSFETs
with an RDS(ON) value specified at VGS = 4.5V can be used.
Select QA and QB. With 18V maximum input voltage MOS-
FETs with a rating of at least 30V are used. As we do not yet
know the actual thermal resistance (circuit board design and
airflow have a major impact) we assume that the MOSFET
thermal resistance from junction to ambient is 50°C/W.
If we design for a maximum junction temperature, TJ(MAX)
= 125°C, the maximum RDS(ON) value can be calculated.
First, calculate the maximum power dissipation:
PD(MAX )
=



TJ(MAX) − TA(MAX)
R(j− a)



PD(MAX )
=
(125 −
50
60)
=
1.3W
The maximum dissipation in QA occurs at minimum input
voltage when the circuit operates in the boost region and
QA is on continuously. The input current is then:
VOUT • IOUT(MAX) , OR 12A
VIN(MIN)
We calculate a maximum value for RDS(ON):
RDS(ON) (125°C)
<
PD(MAX )
IIN(MAX) 2
RDS(ON) (125°C)
1.3W
< (12A)2
=
0.009Ω
For more information www.linear.com/LTC3789
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