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LTC3124_15 Datasheet, PDF (19/28 Pages) Linear Technology – 15V, 5A 2-Phase Synchronous Step-Up DC/DC Converter with Output Disconnect
LTC3124
APPLICATIONS INFORMATION
– MODULATOR
+gmp
IL
η • VIN
2 • VOUT
• IL
VOUT
RESR RL
ERROR
AMPLIFIER
1.2V
REFERENCE
COUT
RPL
VC gma
FB
CPL R1
RC
CF
RO
R2
CC
CC: COMPENSATION CAPACITOR
RC: COMPENSATION RESISTOR
3124 F07
CF: HIGH FREQUENCY FILTER CAPACITOR
CPL: PHASE LEAD CAPACITOR
RPL: PHASE LEAD RESISTOR
gma: TRANSCONDUCTANCE AMPLIFIER INSIDE IC
RO: OUTPUT RESISTANCE OF gma
gmp: POWER STAGE TRANSCONDUCTANCE AMPLIFIER
COUT: OUTPUT CAPACITOR
RESR: OUTPUT CAPACITOR ESR
RL: OUTPUT RESISTANCE DEFINED AS VOUT/ILOAD(MAX)
R1, R2: FEEDBACK RESISTOR DIVIDER NETWORK
η: CONVERSION EFFICIENCY (~90% AT HIGHER CURRENTS)
Figure 7. Boost Converter Equivalent Model
Combining the two equations above yields:
GDC
=
GMP
•
GPOWER
≈
3.4
•
η• VIN
VOUT
• RL
V/V
Converter efficiency η will vary with IOUT and switching
frequency fSWITCH as shown in the typical performance
characteristics curves.
Output Pole: P1 =
2
Hz
2π •RL •COUT
Error Amplifier Pole:
P2
=
2π
•
RO
1
• (CC
+
CF
)
Hz;
CF
<
CC
10
≈ 1 Hz; ExtremelyClose toDC
2π •RO •CC
Error Amplifier Zero: Z1 =
1 Hz
2π •RC •CC
ESR Zero: Z2 =
1
Hz
2π •RESR •COUT
RHP Zero: Z3 = VIN2 • 2RL Hz
2π • VOUT2 •L
High Frequency Pole: P3 > fOSC Hz
3
Phase
Lead Zero: Z4
=
1
2π •(R1+RPL ) •CPL
Hz
Phase
Lead Pole:
P4 =
1
2π
•


R1•R2
R1+ R2
+
RPL


•
CPL
Hz
Error Amplifier Filter Pole:
P5
=
2π
•RC
1
• CC •CF
CC + CF
Hz,
CF
<
CC
10
≈ 1 Hz
2π •RC •CF
The current mode zero (Z3) is a right-half plane zero
which can be an issue in feedback control design, but is
manageable with proper external component selection.
Also note that the RHP zero is a minimum at minimum
input voltage and maximum output current for a given
output voltage. As a general rule, the frequency at which
the open-loop gain of the converter is reduced to unity,
known as the crossover frequency fC , should be set to
less than one-sixth of the right-half plane zero (Z3), and
under one-eighth of the switching frequency fSWITCH. Once
fC is selected, the compensation component values can
be calculated using a Bode plot of the power stage or two
generally valid assumptions: P1 dominates the gain of the
power stage for frequencies lower than fC and fC is much
higher than P2. First calculate the power stage gain at fC,
GfC in V/V. Assuming the output pole P1 dominates GfC
for this range, it is expressed by:
G fC ≈
GDC V/V
1+


PfC1
2
3124f
For more information www.linear.com/LTC3124
19