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ISL24211_14 Datasheet, PDF (7/12 Pages) Intersil Corporation – Programmable VCOM Calibrator with EEPROM and Output Buffer
ISL24211
The maximum value of IDVR_OUT can be calculated by
substituting the maximum register value of 255 into Equation 2,
resulting in Equation 3:
IDVROUT(MAX)
=
----A----V---D----D-----
20 RS E T
(EQ. 3)
Equation 2 can also be used to calculate the unit sink current
step size per Register Code, resulting in Equation 4:
ISTEP
=
----------------A----V----D----D-----------------
( 256 ) ( 20 ) ( RS E T )
(EQ. 4)
Determination of RSET
The ultimate goal for the ISL24211 is to generate an adjustable
voltage between two endpoints, VCOM_MIN and VCOM_MAX, with
a fixed power supply voltage, AVDD. This is accomplished by
choosing the correct values for RSET, R1 and R2. The exact value
of RSET is not critical. Values from 1k to more than 100k will
work under most conditions. The following expression calculates
the minimum RSET value:
⎛
⎜
-A----V---D----D--
⎞
⎟
RSET(MIN)
=
⎜
⎜
⎜
⎝
⎝⎛---V----O---U----T---(--M-----I1--N--6-)----–----A--------2-V-------0D--------D-----⎠⎞-⎠⎟⎟⎟
(k
Ω)
(EQ. 5)
Note that this is the absolute minimum value for RSET. Larger
RSET values reduce quiescent power, since R1 and R2 are
proportional to RSET. The ISL24211 is tested with a 5kΩ RSET.
Determination of R1 and R2
With AVDD, VCOM(MIN) and VCOM(MAX) known and RSET chosen
per the above requirements, R1 and R2 can be determined using
Equations 6 and 7:
R1
=
5120
⋅
RSE
T
⎛
⎜
⎝
2----5----6V----C-⋅--O-V---MC---O-(--M-M----A-(--M-X---)-A--–-X----)V---–C----OV---M-C---O-(--M-M----I-(-N-M--)--I--N----)⎠⎟⎞
(EQ. 6)
R2
=
5120
⋅
RSE
T
⎛
⎜
⎝
-2---5----5-----⋅---A----V---D---V-D---C--+-O----VM---C--(--MO----MA----X(--M-)---–-I--N--V-)--C--–--O--2--M--5--(-6-M----⋅-I--NV----)C---O----M-----(--M----A----X---)⎠⎟⎞
(EQ. 7)
Final Transfer Function
The voltage at DVR_OUT can be calculated from Equation 8:
VDVROUT
=
AVDD
⎛
⎜
⎝
--R----1-R--+--2--R-----2--⎠⎟⎞
⎛
⎜1
⎝
–
R-----e---g----i--s---t---e---r---V---a----l--u----e----+-----1--
256
⎛
⎜
⎝
2----0---R-R---1-S----E---T-⎠⎟⎞⎠⎟⎞
(EQ. 8)
With amplifier A2 in the unity-gain configuration (VCOM_OUT tied
to INN as shown in Figure 5), VDVROUT = VCOM_OUT = VCOM.
Example
As an example, suppose the AVDD supply is 15V, the desired
VCOM_MIN= 6.5V and the desired VCOM_MAX = 8.5V. RSET is
arbitrarily chosen to be 7.5kΩ.
First, verify that our chosen RSET meets the minimum
requirement described in Equation 5:
( 7.5 k Ω )
>
⎛
⎜
⎜
⎜
RSE
T
(MIN
)
⎝
=
⎛
⎜
⎜
------------11--------56----------------⎟⎟⎞
⎜
⎝
⎝⎛ 6.5 V
–
12----50--⎠⎞
⎟
⎠
=
⎞
⎟
0.163 k Ω⎟
⎟
⎠
(EQ. 9)
Using Equations 6 and 7, calculate the values of R1 and R2:
R1
=
5120
⋅
7500
⋅
⎛
⎝
-2---5----6-8----⋅.-5--8--–-.-5-6----.-–5----6----.-5--⎠⎞
=
35.4 k Ω
(EQ. 10)
R2
=
5120
⋅
7500
⋅
⎛
⎝
2----5----5-----⋅---1---5---8--+--.-5--6---–-.-5---6--–-.--5--2---5----6-----⋅---8---.-5-- ⎠⎞
=
46.4 k Ω
(EQ. 11)
Table 1 shows the resulting VCOM voltage as a function of register
value for these conditions.
TABLE 1. EXAMPLE VDVR_OUT vs REGISTER VALUE
REGISTER VALUE
0
VDVR_OUT (V)
8.49
20
8.34
40
8.18
60
8.02
80
7.87
100
7.71
120
7.55
127
7.50
140
7.40
160
7.24
180
7.09
200
6.93
220
6.77
240
6.62
255
6.50
Output Voltage Span Calculation
It is also possible to calculate VCOM(MIN) and VCOM(MAX) from the
existing resistor values.
VCOM_MIN occurs when the greatest current, IDVR(MAX), is drawn
from the middle node of the R1/R2 divider. Substituting
RegisterValue = 255 into Equation 8 gives the following:
VCOM(MIN)
=
A
⎛
VD D ⎝⎜
--R----1-R--+--2--R-----2--⎠⎟⎞
⎛
⎜
⎝
1
–
⎛
⎜
⎝
2----0---R-R---1-S----E---T-⎠⎟⎞
⎞
⎟
⎠
(EQ. 12)
Similarly, RegisterValue = 0 for VCOM(MAX):
VCOM(MAX)
=
A
VD
⎛
D ⎝⎜
--R----1-R--+--2--R-----2--⎠⎟⎞
⎛
⎜
⎝
1
–
----1-----
256
⎛
⎜
⎝
2----0---R-R---1-S----E---T-⎠⎟⎞
⎞
⎟
⎠
(EQ. 13)
7
FN7585.0
February 23, 2011