DG526 Datasheet, PDF (6/16 Pages) Intersil Corporation – Analog CMOS Latchable Multiplexers

DG526, DG527, DG528, DG529
Electrical Specifications (Note 3) V+ = +15V, V- = -15V, GND = 0V, WR = 0V, RS = 2.4V, EN = 2.4V, T_A = 25^oC,
Unless Otherwise Specified (Continued)
A SUFFIX
B AND C SUFFIX
PARAMETER
(NOTE 6)
TEST CONDITIONS
Drain OFF
Capacitance,
C_D(OFF)T
DG526 V_D = 0V
DG527
DG528
V_EN = 0V,
f = 140kHz
DG529
Charge
Injection, Q
DG526, See Figure 8
DG527
(NOTE 2)
MIN
TYP
MAX
-
65
-
-
35
-
-
25
-
-
12
-
-
6
-
(NOTE 2)
MIN
TYP
MAX UNITS
-
65
-
pF
-
35
-
pF
-
25
-
pF
-
12
-
pF
-
6
-
pC
DG528,
DG529
INPUT
Address Input
Current, Input
Voltage High,
I_AH
Address Input
Current, Input
Voltage Low,
I_AL
SWITCH
DG526, V_A = 2.4V
DG527
V_A = 15V
DG528, V_A = 2.4V
DG529
V_A = 15V
DG526 V_EN = 2.4V
DG527
V_EN = 0V
DG528 V_EN = 2.4V
DG529
V_EN = 0V
All V_A = 0V,
RS = 0V,
WR = 0V
-
4
-
-
4
-
pC
-10
0.02
-
-10
0.02
-
µA
-
0.02
10
-
0.02
10
µA
-10
-0.002
-
-10
-0.002
-
µA
-
0.006
10
-
0.006
10
µA
-10
0.01
-
-10
0.01
-
µA
-10
0.01
-
-10
0.01
-
µA
-10
-0.002
-
-10
-0.002
-
µA
-10
-0.002
-
-10
-0.002
-
µA
Analog Signal Range,
V_ANALOG
(Note 7)
-15
-
+15 -15
-
+15
V
Drain Source ON
V_D = ±10V, V_AL = 0.8V, V_AH = 2.4V,
-
Resistance, r_DS(ON)
I_L = -200µA
Sequence Each Switch ON
270
400
-
270
450
Ω
Greatest Change in Drain -10V ≤ V_S ≤ 10V
-
6
-
-
6
-
%
Source ON Resistance
Between Channels,
Dr_DS(ON) = ^{rDS(ON)MAX - rDS(ON)MIN}
∆r_DS(ON)
r_DS(ON)AVG.
Source OFF
Leakage
Current,
I_S(OFF)
DG526, V_EN = 0V
DG527
DG528,
DG529
V_S = ±10V,
V_D = +10V
V_S = ±10V,
V_D = +10V
-1
0.02
1
-
0.02
-
nA
-1
-0.005
1
-5
-0.005
5
nA
Drain OFF
Leakage
Current,
I_D(OFF)
DG526 V_EN = 0V
DG527
V_S = ±10V,
V_D = +10V
V_S = ±10V,
V_D = +10V
-10
0.2
10
-
0.2
-
nA
-5
0.2
5
-
0.2
-
nA
DG528
V_S = ±10V,
V_D = +10V
-10
-0.015
10
-20
0.015
20
nA
DG529
V_S = ±10V,
V_D = +10V
-10
-0.008
10
-20
0.008
20
nA
Drain ON
DG526 Sequence Each V_D = V_S(ALL) =
-10
0.2
10
-
0.2
-
nA
Leakage
Switch On
±10V
Current, I_{D(ON) DG527}
V_AL = 0.8V and
V_AH = 2.4V
(Note 5)
V_D = V_S(ALL) =
±10V
-5
0.2
5
-
0.2
-
nA
12-6