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LT1054_15 Datasheet, PDF (15/33 Pages) Linear Technology – Switched-Capacitor Voltage Converter with Regulator
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LT1054
SLVS033G – FEBRUARY 1990 – REVISED JULY 2015
The power dissipation is equivalent to that of a linear regulator. Limited power-handling capability of the LT1054
packages causes limited output-current requirements, or steps can be taken to dissipate power external to the
LT1054 for large input or output differentials. This is accomplished by placing a resistor in series with CIN as
shown in Figure 16. A portion of the input voltage is dropped across this resistor without affecting the output
regulation. Since switch current is approximately 2.2 times the output current and the resistor causes a voltage
drop when CIN is both charging and discharging, the resistor chosen is as shown:
Rx
=
Vx
4.4 IOUT
where
• VX ≈ VCC − [(LT1054 voltage loss)(1.3) + |VOUT|]
• IOUT = maximum required output current
(7)
The factor of 1.3 allows some operating margin for the LT1054.
When using a 12-V to −5-V converter at 100-mA output current, calculate the power dissipation without an
external resistor.
P = (12 V- | -5 V |)(100 mA) + (12 V)(100 mA)(0.2)
P = 700 mW + 240 mW = 940 mW
(8)
+
CIN
1
FB/SD
Rx 2
CAP+
3
GND
LT1054
4
CAP−
8
VCC
7
OSC
6
VREF
5
VOUT
VIN
R1
R2
VOUT
C1
COUT
+
Pin numbers shown are for the P package.
Figure 16. Power-Dissipation-Limiting Resistor in Series With CIN
At RθJA of 130°C/W for a commercial plastic device, a junction temperature rise of 122°C occurs. The device
exceeds the maximum junction temperature at an ambient temperature of 25°C. To calculate the power
dissipation with an external resistor (RX), determine how much voltage can be dropped across RX. The maximum
voltage loss of the LT1054 in the standard regulator configuration at 100 mA output current is 1.6 V.
VX = 12 V – [(1.6 V)(1.3) + |–5 V|] = 4.9 V
(9)
and
Rx
=
4.9 V
(4.4)(100 mA)
= 11 W
(10)
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