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MIC2582_09 Datasheet, PDF (18/25 Pages) Micrel Semiconductor – Single Channel Hot Swap Controllers
Micrel, Inc.
For additional information on MOSFET thermal
considerations, please see MOSFET Selection text and
subsequent sections.
Auto-Restart - MIC2583R
The MIC2583R provides an auto-restart function. Upon
an overcurrent fault condition such as a short circuit, the
MIC2583R initially shuts off the GATE output. The
MIC2583R attempts to restart with a 12µA charge
current at a preset 10% duty cycle until the fault
condition is removed. The interval between auto-retry
attempts is set by capacitor CFILTER.
Sense Resistor Selection
The MIC2582 and MIC2583 use a low-value sense
resistor to measure the current flowing through the
MOSFET switch (and therefore the load). This sense
resistor is nominally set at 50mV/ILOAD(CONT). To
accommodate worst-case tolerances for both the sense
resistor (allow ±3% over time and temperature for a
resistor with ±1% initial tolerance) and still supply the
maximum required steady-state load current, a slightly
more detailed calculation must be used.
The current limit threshold voltage (i.e., the “trip point”)
for the MIC2582/83 may be as low as 42mV, which
would equate to a sense resistor value of
42mV/ILOAD(CONT). Carrying the numbers through for the
case where the value of the sense resistor is 3% high
yields:
MIC2582/MIC2583
( )( ) RSENSE(MAX )
=
1.03
42mV
I LOAD(CONT )
= 40.8mV
I LOAD(CONT )
(11)
Once the value of RSENSE has been chosen in this
manner, it is good practice to check the maximum
ILOAD(CONT) which the circuit may let through in the case of
tolerance buildup in the opposite direction. Here, the
worst-case maximum current is found using a 59mV trip
voltage and a sense resistor that is 3% low in value. The
resulting equation is:
( ) ILOAD(CONT,MAX )
=
59mV
(0.97) RSENSE(NOM )
= 60.8mV (12)
RSENSE(NOM )
As an example, if an output must carry a continuous 2A
without nuisance trips occurring, Equation 11
yields:
RSENSE(MAX )
=
40.8mV
2A
= 20.4mΩ.
The next
lowest standard value is 20mΩ. At the other set of
tolerance extremes for the output in question,
I LOAD(CONT ,MAX )
=
60.8mV
20.0mΩ
=
3.04A,
approximately 3A.
Knowing this final data, we can determine the necessary
wattage of the sense resistor using P = I2R, where I will
be ILOAD(CONT, MAX), and R will be (0.97)(RSENSE(NOM)).
These numbers yield the following: PMAX = (3A)2
(19.4mΩ) = 0.175W.
In this example, a ¼W sense resistor is sufficient.
April 2009
Figure 8. 5V Switch/3.3V LDO Application
18
M9999-043009-C