APA150-TQG100 Datasheet, PDF (39/178 Pages) Actel Corporation – ProASICPLUS® Flash Family FPGAs

ProASIC^PLUS Flash Family FPGAs
Logic-Tile Contribution—P_logic
P_logic, the logic-tile component of AC power dissipation, is given by
P_logic = P3 * mc * Fs
where:
P3 = 1.4 μW/MHz is the average power consumption of a logic tile per MHz of its output toggling rate. The
maximum output toggling rate is Fs/2.
mc = the number of logic tiles switching during each Fs cycle
Fs = the clock frequency
I/O Output Buffer Contribution—P_outputs
P_outputs, the I/O component of AC power dissipation, is given by
P_outputs = (P4 + (C_load * V_DDP2)) * p * Fp
where:
P4 =
C_load =
p=
Fp =
326 μW/MHz is the intrinsic power consumption of an output pad normalized per MHz of the output
frequency. This is the total I/O current V_DDP.
the output load
the number of outputs
the average output frequency
I/O Input Buffer's Buffer Contribution—P_inputs
The input’s component of AC power dissipation is given by
P_inputs = P8 * q * Fq
where:
P8 = 29 μW/MHz is the intrinsic power consumption of an input pad normalized per MHz of the input
frequency.
q = the number of inputs
Fq = the average input frequency
PLL Contribution—P_pll
P_pll = P9 * N_pll
where:
P9 = 7.5 mW. This value has been estimated at maximum PLL clock frequency.
N_Pll = number of PLLs used
RAM Contribution—P_memory
Finally, P_memory, the memory component of AC power consumption, is given by
P_memory = P6 * N_memory * F_memory * E_memory
where:
P6
=
N_memory =
F_memory =
E_memory =
175 µW/MHz is the average power consumption of a memory block per MHz of the clock
the number of RAM/FIFO blocks
(1 block = 256 words * 9 bits)
the clock frequency of the memory
the average number of active blocks divided by the total number of blocks (N) of the memory.
• Typical values for E_memory would be 1/4 for a 1k x 8,9,16, 32 memory and 1/16 for a 4kx8,
9, 16, and 32 memory configuration
• In addition, an application-dependent component to E_memory can be considered. For
example, for a 1kx8 memory configuration using only 1 cycle out of 2, E_memory = 1/4*1/2 = 1/8
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