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LTC3601_15 Datasheet, PDF (20/26 Pages) Linear Technology – 1.5A, 15V Monolithic Synchronous Step-Down Regulator
LTC3601
APPLICATIONS INFORMATION
Design Example
As a design example, consider using the LTC3601 in an
application with the following specifications:
VIN = 12V, VOUT = 1.8V, IOUT(MAX) = 1.5A, IOUT(MIN) =
10mA, f = 1MHz
Because efficiency is important at both high and low load
currents, Burst Mode operation is selected.
First, the correct RRT resistor value for 1MHz switching
frequency must be chosen. Based on the equation dis-
cussed earlier, RRT should be 324k.
Next, determine the inductor value for approximately 40%
ripple current using:
L
=



1MHz1•.86V00mA 1 –
1.8V
12V



=
2.55μH
A standard value 2.2μH inductor will work well for this
application.
Next, COUT is selected based on the required output
transient performance and the required ESR to satisfy
the output voltage ripple. For this design, a 22μF ceramic
capacitor will be used.
CIN should be sized for a maximum current rating of:
( ) 
IRMS
=
1.5A



1.8V
12V – 1.8V
12V



=
0.54A

Decoupling the VIN pins with a 22μF ceramic capacitor
should be adequate for most applications. A 0.1μF boost
capacitor should also work for most applications.
To save board space the ITH pin is connected to the INTVCC
pin to select an internal compensation network.
The PGOOD pin is connected to VIN through a 100k resistor.
VIN
4V TO 15V
CIN
22μF
2.2μF
VIN
BOOST
RUN
MODE/SYNC
SW
INTVCC
VON
LTC3601
100k
FB
PGOOD
ITH
TRACK
RT
324k SGND
PGND
3601 F05
C1
0.1μF L1
2.2μH
R3
CFWD
80k
10pF
R4
40k
CIN: TDK C3225X5R1C226M
COUT: TDK C3225X5R0J476M
L1: VISHAY IHLP2020BZER2R2M01
Figure 7. 1.8V, 1.5A Regulator at 1MHz
VOUT
1.8V
COUT 1.5A
47μF
3601fb
20