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ISL6742 Datasheet, PDF (15/18 Pages) Intersil Corporation – Advanced Double-Ended PWM Controller
ISL6742
If ΔVCS is greater than or equal to Ve, then no additional slope
compensation is needed and RCS becomes Equation 22:
RCS
=
------------------------------------------------------------N----C----T-------------------------------------------------------------
N-----S--
NP
⋅
⎛
⎜
⎝
IO
+
D-----t--S----W---
2LO
⋅
⎛
⎝⎜ V I N
⋅
N-----S--
NP
–
⎞⎞
VO⎠⎟
⎟
⎠
+
V-----I--N-----⋅---D-----t--S----W---
Lm
(EQ. 22)
If ΔVCS is less than Ve, then Equation 19 is still valid for the
value of RCS, but the amount of slope compensation added
by the external ramp must be reduced by ΔVCS.
Adding slope compensation is accomplished in the ISL6742
using an external buffer and the CT signal. A typical
application sums the buffered CT signal with the current
sense feedback and applies the result to the CS pin as
shown in Figure 14.
1 VREF
16
2
ISL6742 15
3
14
4 CT
13
5
12
R9
6
11
7 CS
10
8
9
R6
RCS
C4
CT
FIGURE 14. ADDING SLOPE COMPENSATION
Assuming the designer has selected values for the RC filter
(R6 and C4) placed on the CS pin, the value of R9 required
to add the appropriate external ramp can be found by
superposition.
Ve – ΔVCS
=
-2----D------⋅---R-----6---
R6 + R9
V
(EQ. 23)
Rearranging to solve for R9 yields:
R9
=
-(--2----D------–----V----e-----+-----Δ----V----C----S----)----⋅---R----6--
Ve – ΔVCS
Ω
(EQ. 24)
The value of RCS determined in Equation 19 must be
rescaled so that the current sense signal presented at the
CS pin is that predicted by Equation 17. The divider created
by R6 and R9 makes this necessary.
R′CS
=
R-----6-----+-----R-----9--
R9
⋅
RCS
(EQ. 25)
Example:
VIN = 280V
VO = 12V
LO = 2.0µH
NP/NS = 20
Lm = 2mH
IO = 55A
Oscillator Frequency, FSW = 400kHz
Duty Cycle, D = 85.7%
NCT = 50
R6 = 499Ω
Solve for the current sense resistor, RCS, using Equation 19.
RCS = 15.1Ω.
Determine the amount of voltage, Ve, that must be added to
the current feedback signal using Equation 16.
Ve = 153mV
Next, determine the effect of the magnetizing current from
Equation 21.
ΔVCS = 91mV
Using Equation 24, solve for the summing resistor, R9, from
CT to CS.
R9 = 13.2kΩ
Determine the new value of RCS, R’CS, using Equation 25.
R’CS = 15.7Ω
Additional slope compensation may be considered for
design margin. This discussion determines the minimum
external ramp that is required. The buffer transistor used to
create the external ramp from CT should have a sufficiently
high gain (>200) so as to minimize the required base
current. Whatever base current is required reduces the
charging current into CT and will reduce the oscillator
frequency.
Parallel Operation
Parallel operation of converters using the ISL6742 may be
accomplished using the average current signal, IOUT. IOUT
provides a very accurate representation of the output current
and may be used for active current sharing with many
sharing techniques commonly used including master-slave
and average current sharing methods.
Since IOUT represents the average inductor current (CCM
operation), sharing errors introduced by techniques using
peak inductor current are reduced. In particular, the current
sharing error introduced by mismatched switching
frequencies is eliminated.
15
FN9183.2
October 31, 2008