ISL6752_14 Datasheet, PDF (11/16 Pages) Intersil Corporation – ZVS Full-Bridge Current-Mode PWM with Adjustable Synchronous Rectifier Control

ISL6752
Since the peak current limit threshold is 1.00V, the total
current feedback signal plus the external ramp voltage must
sum to this value.
V_e + V_CS = 1
(EQ. 15)
Substituting Equations 13 and 14 into Equation 15 and
solving for R_CS yields Equation 16:
R_CS
=
N_-----P-----⋅_---N_-----C----T-
N_S
⋅
-------------------------¹---------------------------
I_O
+
V_-----O--
L_O
t_S
⎛
W⎝
1_π--
+
D_{-2--⎠⎞}
Ω
(EQ. 16)
For simplicity, idealized components have been used for this
discussion, but the effect of magnetizing inductance must be
considered when determining the amount of external ramp
to add. Magnetizing inductance provides a degree of slope
compensation to the current feedback signal and reduces
the amount of external ramp required. The magnetizing
inductance adds primary current in excess of what is
reflected from the inductor current in the secondary.
ΔI_P
=
V_{-----I--N-----}⋅_---D_-----t_--S----W---
L_m
A
(EQ. 17)
where V_IN is the input voltage that corresponds to the duty
cycle D and L_m is the primary magnetizing inductance. The
effect of the magnetizing current at the current sense
resistor, R_CS, is expressed in Equation 18:
ΔV_CS
=
Δ_-----I_--P-----⋅_---R_----C----S--
N_CT
V
(EQ. 18)
If ΔV_CS is greater than or equal to V_e, then no additional slope
compensation is needed and R_CS becomes Equation 19:
R_CS
=
------------------------------------------------------------^N----^C----^T-------------------------------------------------------------
N_-----S--
N_P
⋅
⎛
⎜
⎝
I_O
+
D_-----t_--S----W---
2L_O
⋅
⎛
⎜
⎝
V_I
N
⋅
N_-----S--
N_P
–
⎞⎞
V_{O⎠⎟}
⎟
⎠
+
-^V----^I--^N-----^â‹---^D-----^t--^S----^W---
L_m
(EQ. 19)
If ΔV_CS is less than V_e, then Equation 16 is still valid for the
value of R_CS, but the amount of slope compensation added
by the external ramp must be reduced by ΔV_CS.
Adding slope compensation may be accomplished in the
ISL6752 using the CTBUF signal. CTBUF is an amplified
representation of the sawtooth signal that appears on the CT
pin. It is offset from ground by 0.4V and is 2x the peak-to-peak
amplitude of CT (0.4V to 4.4V). A typical application sums this
signal with the current sense feedback and applies the result
to the CS pin, as shown in Figure 6.
R9
R6
1
16
2
ISL6752
15
3
14
4 CTBUF
13
5
12
6
11
7
10
8 CS
9
RCS
C4
FIGURE 6. ADDING SLOPE COMPENSATION
Assuming the designer has selected values for the RC filter
placed on the CS pin, the value of R9 required to add the
appropriate external ramp can be found by superposition.
V_e – ΔV_CS
=
-⁽--^D-----⁽--^V----^C-----^T---^B----^U----^F-----–----⁰----^.-⁴----⁾----+-----⁰---^.--⁴---⁾----^â‹---^R-----⁶-
R6 + R9
V
(EQ. 20)
Rearranging to solve for R9 yields Equation 21:
R9
=
(_---D_-----(_--V_{----C-----T---B----U----F-----–----}0_----._-4_----)_{----–----}V_{----e-----+-----}Δ_----V_{----C----S-----+-----}0_----._-4_----)_----⋅_---R_----6_--
V_e – ΔV_CS
Ω
(EQ. 21)
The value of R_CS determined in Equation 16 must be
rescaled so that the current sense signal presented at the
CS pin is that predicted by Equation 14. The divider created
by R6 and R9 makes this necessary.
R′_CS
=
R_-----6_-----+-----R_-----9_--
R9
⋅
R_CS
(EQ. 22)
Example:
V_IN = 280V
V_O = 12V
L_O = 2.0µH
Np/Ns = 20
Lm = 2mH
I_O = 55A
Oscillator Frequency, F_SW = 400kHz
Duty Cycle, D = 85.7%
N_CT = 50
R6 = 499Ω
Solve for the current sense resistor, R_CS, using Equation 16.
R_CS = 15.1Ω.
11
FN9181.3
October 31, 2008