AD9522-3 Datasheet, PDF (45/84 Pages) Analog Devices – 12 LVDS/24 CMOS Output Clock Generator with Integrated 2 GHz VCO

AD9522-3
Duty-cycle correction requires the following channel divider
conditions:
• An even division must be set as M = N.
• An odd division must be set as M = N + 1.
When not bypassed or corrected by the DCC function, the duty
cycle of each channel divider output is the numerical value of
(N + 1)/(N + M + 2) expressed as a percent.
The duty cycle at the output of the channel divider for various
configurations is shown in Table 34 to Table 37.
Table 36. Channel Divider Output Duty Cycle When the
VCO Divider Is Enabled and Set to 1
Input
DX
Output Duty Cycle
Clock
Disable Div
Duty Cycle N + M + 2 DCC = 1
Disable Div DCC = 0
Any
Even
(N + 1)/
50%, requires M = N
(M + N + 2)
50%
Odd
(N + 1)/
50%, requires M = N + 1
(M + N + 2)
X%
Odd
(N + 1)/
(N + 1 + X%)/(2 × N + 3),
(M + N + 2) requires M = N + 1
Table 34. Channel Divider Output Duty Cycle with VCO
Divider ≠ 1, Input Duty Cycle Is 50%
DX
Output Duty Cycle
VCO
Divider
Disable Div
N + M + 2 DCC = 1
Disable Div
DCC = 0
Even
Channel 50%
50%
divider
bypassed
Odd = 3 Channel 33.3%
50%
divider
bypassed
Odd = 5 Channel 40%
50%
divider
bypassed
Even, odd Even
(N + 1)/(N + M + 2)
50%, requires
M=N
Even, odd Odd
(N + 1)/(N + M + 2)
50%, requires
M=N+1
Table 35. Channel Divider Output Duty Cycle with VCO
Divider ≠ 1, Input Duty Cycle Is X%
DX
Output Duty Cycle
VCO
Disable Div
Divider N + M + 2 DCC = 1
Disable Div DCC = 0
Even Channel 50%
50%
divider
bypassed
Odd = 3 Channel 33.3%
divider
bypassed
(1 + X%)/3
Odd = 5 Channel 40%
divider
bypassed
(2 + X%)/5
Even Even
(N + 1)/
50%, requires M = N
(N + M + 2)
Even Odd
(N + 1)/
50%, requires M = N + 1
(N + M + 2)
Odd = 3 Even
(N + 1)/
50%, requires M = N
(N + M + 2)
Odd = 3 Odd
(N + 1)/
(3N + 4 + X%)/(6N + 9),
(N + M + 2) requires M = N + 1
Odd = 5 Even
(N + 1)/
50%, requires M = N
(N + M + 2)
Odd = 5 Odd
(N + 1)/
(5N + 7 + X%)/(10N + 15),
(N + M + 2) requires M = N + 1
Note that the channel divider must be enabled when the VCO
divider = 1.
Table 37. Channel Divider Output Duty Cycle When the
VCO Divider Is Bypassed
Input
DX
Output Duty Cycle
Clock
Disable Div
Duty Cycle N + M + 2 DCC = 1
Disable Div DCC = 0
Any
Channel Same as input Same as input duty
divider duty cycle
cycle
bypassed
Any
Even
(N + 1)/
50%, requires M = N
(M + N + 2)
50%
Odd
(N + 1)/
50%, requires M = N + 1
(M + N + 2)
X%
Odd
(N + 1)/
(N + 1 + X%)/(2 × N + 3),
(M + N + 2) requires M = N + 1
The internal VCO has a duty cycle of 50%. Therefore, when the
VCO divider equals 1, the duty cycle is 50%. If the CLK input is
routed directly to the output, the duty cycle of the output is the
same as the CLK input.
Phase Offset or Coarse Time Delay
Each channel divider allows for a phase offset, or a coarse time
delay, to be programmed by setting register bits (see Table 38).
These settings determine the number of cycles (successive rising
edges) of the channel divider input frequency by which to offset, or
delay, the rising edge of the output of the divider. This delay is
with respect to a nondelayed output (that is, with a phase offset
of zero). The amount of the delay is set by five bits loaded into
the phase offset (PO) register plus the start high (SH) bit for
each channel divider. When the start high bit is set, the delay is
also affected by the number of low cycles (M) programmed for
the divider.
It is necessary to use the SYNC function to make phase offsets
effective (see the Synchronizing the Outputs— Function section).
Table 38. Setting Phase Offset and Division
Start
Phase
Low Cycles
Divider High (SH) Offset (PO) M
0
0x191[4] 0x191[3:0] 0x190[7:4]
1
0x194[4] 0x194[3:0] 0x193[7:4]
2
0x197[4] 0x197[3:0] 0x196[7:4]
3
0x19A[4] 0x19A[3:0] 0x199[7:4]
High Cycles
N
0x190[3:0]
0x193[3:0]
0x196[3:0]
0x199[3:0]
Rev. 0 | Page 45 of 84