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AAT1415 Datasheet, PDF (31/32 Pages) Advanced Analog Technology, Inc. – FIVE-CHANNEL DC-DC CONVERTER WITH A 2.5V LDO
Advanced Analog Technology, Inc.
May 2008
AAT1415/AAT1415A
Set the loop cross over frequency ( fC ) below the lower
of 1/10 the switching frequency ( fSW ). Choose the
compensation capacitor CC to set the desired
crossover frequency fC . Determine the value by the
following equation:
CC
=
( VOUT
VI
+ VREF ) ⋅
× Gm
M 2π ⋅ fC
Where:
M = 2 ⋅ L ⋅ fSW
RLOAD
The RCCC zero is then used to cancel the fP pole,
so:
RC
=
RLOAD ⋅ COUT
2 ⋅ CC
The typical RC is under 500 kΩ .
If the system wants better transient response, it can
parallel a capacitor CU with RUPPER _ from IN_ to
VOUT _ :
CU
=
1

2π
×
56kΩ
×
20kHz
×



VIN _
VOUT _ + VIN _




≈ 1nF
LAYOUT CONSIDERATIONS
Conductors carrying discontinuous currents and any
high-current path should be made as short and wide as
possible. The compensation network should be very
close to the EO_ pin and avoid through VIA. The IC
must be bypassed with ceramic capacitors placed
close to the VDD and VREF. A separate low-noise
ground plane containing the reference and signal
grounds should connect to the power-ground plane at
only one point to minimize the effects of power-ground
currents. Typically, the ground planes are best joined
right at the IC. Tie the feedback resistor divider to be
very close to output capacitor and far away from the
inductor or Schottky diode. Keep the feedback network
(IN_) close to the IC. Switching nodes (SW_) should be
kept as small as possible and should be routed away
from high-impedance nodes such as IN.
CU
=
2π × RUPPER _
1

×
fC
×



VIN _
VOUT _ + VIN _




If CU is calculated to be less than 10pF, it can be
omitted. Additional CU can suppress the inrush current.
So, for a –7V/50mA output with VI = 3.0V, L = 4.7µH,
RUPPER = 56 kΩ , fSW = 500kHz:
CC
=
( −7
3V
+ 1.25V) ⋅
× 70µ A / V ≈ 2.2nF
33.6m 2π ⋅ 20kHz
RC
=
140Ω ⋅10µF
2 ⋅ 2.2nF
≈
300kΩ
,
– 台灣類比科技股份有限公司 –
– Advanced Analog Technology, Inc. –
Version 3.00
Page 31 of 32