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AAT1164 Datasheet, PDF (19/24 Pages) Advanced Analog Technology, Inc. – TRIPLE-CHANNEL TFT LCD POWER SOLUTION
Advanced Analog Technology, Inc.
April 2007
AAT1164/AAT1164B/AAT1164C
Compensator design guide:
1.
Crossover
frequency fci
<
1
2
fS
2. Gain margin>10dB
∘ 3. Phase margin>45
4. The LVI(s) = 1 at crossover frequency, Therefore,
the compensator resistance, RC is determined by:
RC
=
VO
VFB
2πfciCOUTRCS
gmk
(RL + 2rC )

(1−

D)RL
−
r
(1−
D)



Bode Diagram
60
40
20
0
-20
-40
-90
-135
-180
-225
-270
2
3
4
5
6
10
10
10
10
10
Frequency (Hz)
Figure 7. Bode Plot of Loop Gain Using Matlab®
Simulation
Table 3. k Factor Table
COUT
Best Corner
Frequency
21.533µF
23.740kHz
25.079µF
21.842kHz
32.587µF
20.095kHz
36.312µF
15.649kHz
38.469µF
13.247kHz
k Factor
4.692
5.083
6.042
5.230
4.703
Positive and Negative LDO Driver
Output Voltage Selection
The output voltage of positive LDO driver is set by a
resistive divider from the output (VOUT3) to GND with the
center tap connected to the IN3, where VIN3, the positive
LDO driver feedback regulation voltage, is 1.25V.
Choose R6 (Figure 8) between 10kΩ and 51kΩ . And
calculate R5 with the following equation.
5. The output filter capacitor is chosen so COUTRL
pole cancels RCCC zero
εRCCC
= COUT


RL
2

+ rC  ,
and
CC
=
COUT
εRC


RL
2

+ rC 
ε = (1 ~ 3)
Example 3:
VIN = 5V, VO = 13.3V, IO = 300mA, fS = 1,190kHz,
VFB = 1.233V, L = 6.65µH, gm = 85µS,
rL = 76.689 mΩ
rC = 9.13 mΩ , RF = 0.7667 Ω , CC = 1.95nF,
RC = 7.6 kΩ , COUT = 38.5 µ F , ε = 3, RCS = 0.23V/A.
R5

=
R6


VOUT3
VIN3

− 1

The output voltage of negative LDO driver is set by a
resistive divider from the output (VOUT2) to VREF with
the center tap connected to IN2, where VIN2, the
negative LDO driver feedback regulation voltage, is
0.25V. Choose R9 (Figure 9) between10kΩ and
51kΩ and calculate R8 with the following equation.
R8
=
R9



VIN2 − VOUT2
VREF − VIN2



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