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LOG104_14 Datasheet, PDF (8/15 Pages) Texas Instruments – LOGARITHMIC AND LOG RATIO AMPLIFIER
INSIDE THE LOG104
Using the base-emitter voltage relationship of matched
bipolar transistors, the LOG104 establishes a logarith-
mic function of input current ratios. Beginning with the
base-emitter voltage defined as:
VBE
=
VT
ln
IC
IS
where :
VT
=
kT
q
(1)
k = Boltzmann’s constant = 1.381 • 10–23
T = Absolute temperature in degrees Kelvin
q = Electron charge = 1.602 • 10–19 Coulombs
IC = Collector current
IS = Reverse saturation current
From the circuit in Figure 11, we see that:
VL = VBE1 – VBE2
(2)
Substituting (1) into (2) yields:
VL
=
VT1
ln
I1
IS1
– VT2
ln I 2
IS2
(3)
If the transistors are matched and isothermal and
VTI = VT2, then (3) becomes:
VL
=
VT1

ln

I1
IS
–
ln
I2
IS



(4)
VL
=
VT
ln I1
I2
and since
(5)
ln x = 2.3 log10 x
(6)
VL
=
n VT
log I1
I2
(7)
where n = 2.3
(8)
also
or
VOUT
=
VL
R1 + R2
R1
VOUT
=
R1 + R2
R1
n
VT
log
I1
I2
VOUT
=
0.5V • log I1
I2
(9)
(10)
(11)
I1
I1
Q1 –
– Q2
+
+
VBE1 VBE2
I2
A2
VOUT
A1
VOUT = (0.5V) LOG
I1
I2
R2
I2
VL
R1
FIGURE 11. Simplified Model of a Log Amplifier.
DEFINITION OF TERMS
TRANSFER FUNCTION
The ideal transfer function is:
VOUT = 0.5V • logI1/I2
(5)
See Figure 12 for the graphical representation of the transfer
over valid operating range for the LOG104.
ACCURACY
Accuracy considerations for a log ratio amplifier are some-
what more complicated than for other amplifiers. This is
because the transfer function is nonlinear and has two
inputs, each of which can vary over a wide dynamic range.
The accuracy for any combination of inputs is determined
from the total error specification.
3.5
3.0
2.5
2.0
1.5
1.0
0.5
0.0
–0.5
–1.0
–1.5
–2.0
–2.5
–3.0
–3.5
I2=
I2=
I2=
100pA
1nA
10nA
100pA 1nA 10nA
I
I
I
I
I
2
2
2
2
2
=
=
=
=
=
100nA
11100µ0µAµAA
1mA
100nA 1µA 10µA 100µA 1mA
VOUT = (0.5V) • LOG (I1/I2)
10mA
I1
FIGURE 13. Transfer Function with Varying I2 and I1.
8
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LOG104
SBOS243C