English
Language : 

SC2440 Datasheet, PDF (20/26 Pages) Semtech Corporation – 2.5 MHz Dual Switching Regulator with Integrated 2A Switches
SC2440
POWER MANAGEMENT
Applications Information
In addition C5 and R5 form a zero with angular frequency:
ωZ1
=
−
1
R5C
5
=
−
15.4
1
KΩ ⋅
470pF
= −140 Krads−1 = −22KHz
The output-to-control transfer function
vCOMP
vOUT
=
vCOMP
vFB
⋅
vFB
vOUT
is
also
shown
in
Figure
13.
Its
mid-
band
gain
(between
z1
and
p3)
is
GMAR5

R2
R1 + R2

.
The
overall loop gain T(s) is the product of the control-to-
output and the output-to-control transfer functions. To
simplify T( jω) Bode plot, the feedback network is
assumed to be resistive. If the overall loop gain is to
cross 0dB at one tenth of the switching frequency
( ωC
=
ωS
10
=
πf
5
)
at
–20dB/decade,
then
its
mid-band
gain
(between z1 and p2) will be
ωc
ωp2
=
ωS
10
n
C1ROUT
=
ωSC1ROUT
10n
.
This is also equal to
GMPROUTGMAR5

R2
R1 + R2

.
Therefore
the crossover frequency. However it reduces the phase
m(1a1r)gainn.dA(1n2e)swtiimthant=e1o.fThRe5 caonmdpCe5ncsaantiobneisotbhteanincehdecfrkoemd
by measuring the loop gain and the phase or by observing
the inductor current and the output voltage during load
transient. Choose
give at least 45°
othf ephlaarsgeesmt Rar5gainn.dTthhee
csomrraellsepsotnCd5intog
load transient should not show any ringing or excessive
oisvaerssmhoaolltc(esreaemFiicgucarepsac1i4to(cr)(,1104-4(d7)p, F1)7t(ob)roalnl odff1t7h(ec)l)o. oCp6
gain at
phase
high frequency.
margin over a
FliemeidtefodrwfraerqduceanpcaycirtoarnCge11
boosts
and is
sometimes used to improve loop response. C11 will be
more effective if R1 >> R1R2 .
Example: Determine the compensation components for
the 1.3MHz 12V to 5V and 3.3V converter in Figure 1.
For both channels, ωS = 8.2Mrads−1 , IOUT(MAX) = 2A and
C1 = 10µF . n is assumed to be 1 in (11) and (12).
For the 3.3V output:
R5
=
1
+
23.3K
10K

10
8.2×106 ⋅10−5
⋅ (1) ⋅ (5.7) ⋅ (2.8 ×10−4 )
= 16.9KΩ
C5
=
10−5 ⋅ 3.3V
(1) ⋅16.9K ⋅ (2A)
= 1nF
For the 5V channel:
GMPROUT
GMAR5

R2
R1 + R2

=
ωC1ROUT
10n
.
Re-arranging,
R7
=
1
+
40.2K
10K

10
8.2 ×106 ⋅10−5
⋅ (1) ⋅ (5.7) ⋅ (2.8 ×10−4
)
= 25.5KΩ
R5
=
1
+
R1
R2

ωSC1
10nGMPGMA
(11)
ωz1 is shown to be less than ωp2 in Figure 13. Making
ωz1 = ωp2 gives a first-order estimate of C5:
C5
=
C1ROUT (MIN)
nR5
(12)
Ncoontivceerttehra. ItnRc5redaestienrgmRin5einsctrheeasmeisdt-hbaenmdidlo-boapngdaginaionf
the
and
C8
=
(1)
10−5 ⋅ 5V
⋅25.5K ⋅(2A)
=
1nF
Cm6aargnidn.CL9o(abdotthra1n0sipeFn)t
are then added to
responses of both
increase gain
channels are
observed using these values. There is very little inductor
current overshoot even
and 220pF respectively
(wFiitghurCe5
and
14).
TCh8eremdeuacseudretod
470pF
overall
loop gain and phase plots of the converter are also
shown.
© 2005 Semtech Corp.
20
www.semtech.com