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MIC5190 Datasheet, PDF (11/13 Pages) Micrel Semiconductor – Ultra High-Speed, High-Current Active Filter/LDO Controller
MIC5190
Feedback Resistors
IR3716S
VOUT
MIC5190
FB
R1
R2
COUT
GND
Figure 10. Adjustable Output
The feedback resistors adjust the output to the desired
voltage and can be calculated as follows:
VOUT
=

VREF 1+
R1
R2
VREF is equal to 0.5V for the MIC5190. The minimum output
voltage (R1=0) is 0.5V. For output voltages greater than 1V,
use the MIC5191.
The resistor tolerance adds error to the output voltage. These
errors are accumulative for both R1 and R2. For example, our
resistors selected have a ±1% tolerance. This will contribute
to a ±2% additional error on the output voltage.
The feedback resistors must also be small enough to allow
enough current to the feedback node. Large feedback resis-
tors will contribute to output voltage error.
VERROR = R1× IFB
VERROR = 1kΩ × 12µA
VERROR = 12mV
For our example application, this will cause an increase in
output voltage of 12mV. For the percentage increase,
Micrel
Active Filter
Another application for the MIC5190 is as an active filter on
the output of a switching regulator. This improves the power
supply in several ways.
First, using the MIC5190 as a filter on the output can signifi-
cantly reduce high frequency noise. Switching power sup-
plies tends to create noise at the switching frequency in the
form of a triangular voltage ripple. High frequency noise is
also created by the high-speed switching transitions. A lot of
time, effort , and money are thrown into the design of
switching regulators to minimize these effects as much as
possible. Figure 9 shows the MIC5190 as a post regulator.
VOUT = 1V
ILOAD = 10A
TIME (1µs/div)
Figure 11. Ripple Reduction
Figure 11 shows the amount of ripple reduction for a 500 kHz
switching regulator. The fundamental switching frequency is
reduced from greater than 100mV to less than 10mV.
VERROR %
=
VERROR
VOUT
× 100
VERROR %
=
12mV
1.5V
×
100
VERROR% = 0.8%
By reducing R1 to 100Ω, the error contribution by the feed-
back resistors and feedback current is reduced to less than
0.1%. This is the reason R1 should not be greater than 100Ω.
Applying the MIC5190
Linear Regulator
The primary purpose of the MIC5190 is as a linear regulator,
which enables an input supply voltage to drop down through
the resistance of the pass element to a regulated output
voltage.
TIME (100µs/div)
Figure 12. 10A Load Transient
The transient response also contributes to the overall AC
output voltage deviation. Figure 12 shows a 1A to 10A load
transient. The top trace is the output of the switching regulator
(same circuit as Figure10). The output voltage undershoots
by 100mV. Just by their topology, linear regulators have the
ability to respond at much higher speeds than a switching
regulator. Linear regulators do not have the limitation or
restrictions of switching regulators which must reduce their
bandwidth to less than their switching frequency.
April, 2004
11
M9999-042804