MIC5216_07 Datasheet, PDF (10/13 Pages) Micrel Semiconductor – 500mA-Peak Output LDO Regulator

Micrel, Inc.
455mW = ⎜⎛ ^{%Duty Cycle} ⎟⎞1.66W
⎝ ¹⁰⁰ ⎠
0.274 = ⎜⎛ ^{%Duty Cycle} ⎟⎞
⎝ ¹⁰⁰ ⎠
% Duty Cycle Max = 27.4%
With an output current of 500mA and a three-volt drop
across the MIC5216-xxBMM, the maximum duty cycle is
27.4%.
Applications also call for a set nominal current output
with a greater amount of current needed for short
durations. This is a tricky situation, but it is easily
remedied. Calculate the average power dissipation for
each current section, then add the two numbers giving
the total power dissipation for the regulator. For
example, if the regulator is operating normally at 50mA,
but for 12.5% of the time it operates at 500mA output,
the total power dissipation of the part can be easily
determined. First, calculate the power dissipation of the
device at 50mA. We will use the MIC5216-3.3BM5 with
5V input voltage as our example.
P_D × 50mA = (5V – 3.3V) × 50mA + 5V × 650µA
MIC5216
P_D × 50mA = 173mW
However, this is continuous power dissipation, the actual
on-time for the device at 50mA is (100%-12.5%) or
87.5% of the time, or 87.5% duty cycle. Therefore, P_D
must be multiplied by the duty cycle to obtain the actual
average power dissipation at 50mA.
P_D × 50mA = 0.875 × 173mW
P_D × 50mA = 151mW
The power dissipation at 500mA must also be
calculated.
P_D × 500mA = (5V – 3.3V) 500mA + 5V × 20mA
P_D × 500mA = 950mW
This number must be multiplied by the duty cycle at
which it would be operating, 12.5%.
P_D × = 0.125mA × 950mW
P_D × = 119mW
a. 25°C Ambient
b. 50°C Ambient
c. 85°C Ambient
Figure 1. MIC5216-x.xBM5 (SOT-23-5) on Minimum Recommended Footprint
a. 25°C Ambient
b. 50°C Ambient
c. 85°C Ambient
Figure 2. MIC5216-x.xBM5 (SOT-23-5) on 1-inch² Copper Cladding
March 2007
10
M9999-032307