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MAX15020 Datasheet, PDF (14/19 Pages) Maxim Integrated Products – 2A, 40V Step-Down DC-DC Converter with Dynamic Output-Voltage Programming
2A, 40V Step-Down DC-DC Converter with
Dynamic Output-Voltage Programming
Compensation Design
The MAX15020 uses a voltage-mode control scheme
that regulates the output voltage by comparing the
error-amplifier output (COMP) with an internal ramp to
produce the required duty cycle. The output lowpass
LC filter creates a double pole at the resonant frequen-
cy, which has a gain drop of -40dB/decade. The error
amplifier must compensate for this gain drop and
phase shift to achieve a stable closed-loop system.
The basic regulator loop consists of a power modulator,
an output feedback divider, and a voltage error amplifi-
er. The power modulator has a DC gain set by VIN /
VRAMP, with a double pole and a single zero set by the
output inductance (L), the output capacitance (COUT)
(C6 in the Figure 2) and its ESR. The power modulator
incorporates a voltage feed-forward feature, which auto-
matically adjusts for variations in the input voltage
resulting in a DC gain of 9. The following equations
define the power modulator:
GMOD(DC)
=
VIN
VRAMP
=9
fLC = 2π
1
L×C
fESR
=
2π
×
1
COUT
×
ESR
The switching frequency is internally set at 300kHz or
500kHz, or can vary from 100kHz to 500kHz when driven
with an external SYNC signal. The crossover frequency
(fC), which is the frequency when the closed-loop gain is
equal to unity, should be set as fSW / 2π or lower.
The error amplifier must provide a gain and phase
bump to compensate for the rapid gain and phase loss
from the LC double pole. This is accomplished by utiliz-
ing a Type 3 compensator that introduces two zeros
and three poles into the control loop. The error amplifier
has a low-frequency pole (fP1) near the origin.
In reference to Figures 3 and 4, the two zeros are at:
fZ1
=
2π
1
× R9 ×
C12
and
fZ2
=
2π
×
(R6
1
+ R7)
× C11
And the higher frequency poles are at:
fP2
=
2π
×
1
R6
× C11
and
fP3
=
2π
× R9
×
1
⎛ C12
⎝⎜ C12
× C13 ⎞
+ C13⎠⎟
Compensation when fC < fESR
Figure 3 shows the error-amplifier feedback as well as
its gain response for circuits that use low-ESR output
capacitors (ceramic). In this case fZESR occurs after fC.
fZ1 is set to 0.8 x fLC(MOD) and fZ2 is set to fLC to com-
pensate for the gain and phase loss due to the double
pole. Choose the inductor (L) and output capacitor
(COUT) as described in the Inductor Selection and
Output Capacitor Selection sections.
Choose a value for the feedback resistor R6 in Figure 3
(values between 1kΩ and 10kΩ are adequate).
C12 is then calculated as:
C12 =
1
2π × 0.8 × fLC × R9
fC occurs between fZ2 and fP2. The error-amplifier gain
(GEA) at fC is due primarily to C11 and R9.
Therefore, GEA(fC) = 2π x fC x C11 x R9 and the modu-
lator gain at fC is:
GMOD(fC)
=
(2π)2
GMOD(DC)
× L × COUT
×
fC2
Since GEA(fC) x GMOD(fC) = 1, C11 is calculated by:
C11 = fC × L × COUT × 2π
R9 × GMOD(DC)
fP2 is set at 1/2 the switching frequency (fSW). R6 is
then calculated by:
R6 =
1
2π × C11× 0.5 × fSW
Since R7 >> R6, R7 + R6 can be approximated as R7.
R7 is then calculated as:
R7 =
1
2π × fLC × C11
fP3 is set at 5 x fC. Therefore, C13 is calculated as:
C13 =
C12
2π × C12 × R9 × fP3 − 1
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