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LTC3631 Datasheet, PDF (15/22 Pages) Linear Technology – High Effi ciency, High Voltage 100mA Synchronous Step-Down Converter
LTC3631
APPLICATIONS INFORMATION
The RDS(ON) for both the top and bottom MOSFETs can be
obtained from the Typical Performance Characteristics
curves. Thus, to obtain the I2R losses, simply add RSW
to RL and multiply the result by the square of the average
output current:
I2R Loss = IO2(RSW + RL)
Other losses, including CIN and COUT ESR dissipative
losses and inductor core losses, generally account for
less than 2% of the total power loss.
Thermal Considerations
The LTC3631 does not dissipate much heat due to its high
efficiency and low peak current level. Even in worst-case
conditions (high ambient temperature, maximum peak
current and high duty cycle), the junction temperature will
exceed ambient temperature by only a few degrees.
Design Example
As a design example, consider using the LTC3631 in an
application with the following specifications: VIN = 24V,
VOUT = 3.3V, IOUT = 100mA, f = 250kHz. Furthermore, assume
for this example that switching should start when VIN is greater
than 12V and should stop when VIN is less than 8V.
First, calculate the inductor value that gives the required
switching frequency:
L
=



3.3V
250kHz • 225mA



•

1–

3.3V
24V




47μH
Next, verify that this value meets the LMIN requirement.
For this input voltage and peak current, the minimum
inductor value is:
LMIN
=
24V • 100ns
225mA
≅
10μH
Therefore, the minimum inductor requirement is satisfied,
and the 47μH inductor value may be used.
Next, CIN and COUT are selected. For this design, CIN should
be sized for a current rating of at least:
IRMS
=
100mA
•
3.3V
24V
•
24V
3.3V
–
1
≅
35mARMS
Due to the low peak current of the LTC3631, decoupling
the VIN supply with a 1μF capacitor is adequate for most
applications.
COUT will be selected based on the ESR that is required to
satisfy the output voltage ripple requirement. For a 50mV
output ripple, the value of the output capacitor ESR can
be calculated from:
ΔVOUT = 50mV ≤ 225mA • ESR
A capacitor with a 200mΩ ESR satisfies this requirement.
A 10μF ceramic capacitor has significantly less ESR than
200mΩ.
The output voltage can now be programmed by choosing
the values of R1 and R2. Choose R2 = 240k and calculate
R1 as:
R1
=



VOUT
0.8V
–

1

• R2
=
750k
The undervoltage lockout requirement on VIN can be
satisfied with a resistive divider from VIN to the RUN and
HYST pins. Choose R1 = 2M and calculate R2 and R3 as
follows:
R2
=


1.21V
VIN(RISING) –
1.21V


•
R1
=
224k
R3
=


1.1V
VIN(FALLING)
–
1.1V


•
R1–
R2
=
90.8k
Choose standard values for R2 = 226k and R3 = 91k.
The ISET pin should be left open in this example to select
maximum peak current (225mA). Figure 9 shows a
complete schematic for this design example.
VIN
24V
VIN
SW
2M
LTC3631
47μH
VOUT
3.3V
100mA
1μF
RUN
ISET
10μF
226k
SS
750k
HYST
VFB
91k
GND
240k
3631 F09
Figure 9. 24V to 3.3V, 100mA Regulator at 250kHz
3631fb
15