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AN4138 Datasheet, PDF (9/20 Pages) STMicroelectronics – This application note presents the HSP061-2
APPLICATION NOTE
AN4138
where Vo is the output voltage, VOP is opto-diode forward
voltage drop, which is typically 1V and IFB is the feedback
current of FPS. With IFB=0.25mA (FSD210), Rd and Rbias
are determined as 56Ω and 510Ω, respectively.
Constant Current (CC) control : The current control
circuit is shown in detail in Figure 14. The CC control is
implemented using a transistor. Because the transistor base-
emitter voltage drop varies with the temperature, negative
thermal coefficient (NTC) thermistor is used for a
temperature compensation.
IFB /2
+
VOP
-
Rd
56Ω
1Ω
Rsense
Io = 0.65A
10kΩ
RTH
Vsense
510Ω
Rbias
e
c
IC
VBE
b
Q
IB
KSP2222
IRTH
Rbase
510Ω
KA431
IC
=
(---2---5----0---µ----A------⋅-5--5-1--6-0---Ω-Ω----)---⁄---2-----+-----1----V--
+
1--
2
⋅
250µA
=
2.1mA
By assuming that the current gain (β) of Q is 100, the
transistor base current is obtained as
IB
=
I-β-C--
=
2----.-1----m-----A---
100
=
21uA
(32)
The voltage drop in the sensing resistor (Vsense) should be set
to be 40-100mV higher than the transistor base-emitter
voltage (VBE) at room temperature (25°C). The actual
transistor base-emitter voltage (VBE) temperature is
measured at room temperature as 0.608V with IC of 2.1mA
and Vsense is determined to be 0.650V.
With the Vsense chosen, the sensing resistor (Rsense) is
obtained as
Rsense
=
V-----s--e---n---s---e-
Io
=
0----.--6---5---V---
0.65A
=
1Ω
(33)
where Io is SMPS output current.
It is typical to design the NTC thermistor so that the current
through the thermistor would be about 3-6 times of the
transistor base current at room temperature. The resistance
of the thermistor at room temperature (RTH) is determined as
10 kΩ. The current through the thermistor is obtained as
Figure 14. Current control circuit in detail
When the voltage across the sensing resistor is sufficient to
turn on the transistor, CC controller is enabled while CV
controller is disabled. Then, the KA431 consumes very small
current and most of the currents through Rd and Rbias flow
into the collector of the transistor Q. By assuming that the
feedback voltage of FPS (VFB) is in the middle of its
operating range, half of the FPS feedback current (IFB) sinks
into the opto-coupler transistor. Since it is also assumed that
the CTR of the opto-coupler is 100%, the transistor collector
current is given by
IC
=
(---I--F---B-----⋅---R----d---)----⁄--2-----+------V----o---p-
Rbias
+
1--
2
⋅
IFB
(31)
where IFB is the feedback current of FPS, VOP is opto-diode
forward voltage drop, which is typically 1V.
IRTH
=
-V----B---E--
RTH
=
0---1-.--60---0-k--8-Ω---V--
=
61µA
(34)
The base resistor is determined by
Rbase
=
V-----s--e---n---s---e----–-----V----B---E--
-V----B---E--
RTH
+
IB
=
-0---.--6---5----V-----–----0----.--6---0---8----V--
0---1-.-6-0---0-k--8-Ω---V-- + 21µA
=
513Ω
(35)
Variations in the junction temperature of Q will cause
variations in the value of controlled output current (Io). The
base-emitter voltage decreases with increasing temperature
at a rate of approximately 2mV/°C. When the base-emitter
voltage is changed to VBET as the temperature changes to T
°C, the thermistor resistance at T °C required to compensate
this variation is given by
RT
T
H
=
------------------V----B----E---T-------------------
V-----s--e---n---s---e----–-----V----B---E----T-
Rbase
–
IB
(36)
From the circuit in Figure 14, IC is obtained as
With -2mV/°C, VBE reduces to 0.508V from 0.608V as
temperature increases from 25°C to 75°C. From equation
©2003 Fairchild Semiconductor Corporation
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