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IW1692 Datasheet, PDF (9/18 Pages) Dialog Semiconductor – Low-Power Off-line Digital PWM Controller
iW1692
Low-Power Off-line Digital PWM Controller
10.0 Design Example
10.1 Design Procedure
This design example gives the procedure for a flyback
converter using iW1692. Refer to figure 12.0.1 for the
application circuit. The design objectives for this adapter
are given in table 10.1. It meets UL, IEC, and CEC
requirements.
Determine the Design Specifications
(Vout, Iout_max, Vin_max, Vin_min, efficiency, and ripple)
Determine Output Voltage
Parameter
Input Voltage
Frequency
No Load Input
Output Voltage
Output Current
Output Ripple
Power Out
Symbol
VIN
fIN
PIN
VOUT_PCB
IOUT
VRIPPLE
POUT
Range
s 85 - 264 VRMS
n 47 - 64 Hz
ig 200 mW
4.95 - 5.05 V
s1 A
e<100 mV
D 5 W
Determine Rvin Resistors
Determine Turns Ratio
Determine Input Bulk Capacitance
Determine Current Sensing Resistor
Determine Magnetizing Inductance
Determine Primary Turns
CEC Efficiency
h
65%
Table 10.1 iW1692 Design Specification Table
ew 10.2 Output Voltage
Use equation 10.1 for VOUT in the following equations, where
N VFD is the forward voltage of the output diode:
r = VOUT VOUT (PCB) + VFD
(10.1)
Fo Since no cable is used and the forward drop on the output
Determine Secondary Turns
d Can you wind this transformer ?
No
e Yes
nd Determine Bias Turns
Determine Vsense Turns and Resistors
Determine Output Capacitance
me Determine Snubber Network
diode (VFD) is 500 mV, VOUT is 5.0 V.
10.3 Input Selection
VIN resistors are chosen primarily to scale down the input
voltage for the IC. The scale factor for the input voltage in the
IC is 0.0043 and the internal impedance of this pin is 20 kΩ.
Therefore, the VIN resistors should equate to:
= RVin
20kW − 2= 0kW
0.0043
4.63M W
(10.2)
Determine Ton Delay Compensation
m Finish
Not Reco Figure 10.0.1 iW1692 Design Flow Chart
From equation 10.2, ideally RVIN should be 4.63 MΩ because
R10 and R11 add up to approximately 4.6 MΩ. By selecting
the value of RVIN, the (VIN·TON)MAX_LIMIT and (VIN·TON)PFM are
determined:
(VIN
⋅ TON
)MAX _ LIMIT
= 0.0043×

900V ⋅m s
20kW



RVin
+
20kW


(10.3)
(VIN
) ⋅TON PFM
=0.0043×

185V ⋅m s
20kW



RVin
+
20kW


(10.4)
Keep in mind by changing RVIN to be something other than
4.63 MΩ the minimum and maximum input voltage for start-
up will also change.
Rev. 2.0
iW1692
February 13, 2012
Page 9