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AME5283 Datasheet, PDF (9/20 Pages) Analog Microelectronics – Rectified Step-Down Converter
AME
AME5283
2A, 300KHz ~ 2MHz Synchronous
Rectified Step-Down Converter
Loop Compensation
The AME5283 employs peak current mode control for
easy use and fast transient response. Peak current mode
control eliminates the double pole effect of the output LC
filter. It greatly simplifies the compensation loop design.
With peak current mode control, the buck power stage
can be simplified to be a one-pole and one-zero system
in frequency domain. The pole can be calculated by:
f P1
=
2π
1
× COUT
×
RL
The zero is a ESR zero due to output capacitor and its
ESR. It can be calculated by:
fZ1
=
2π
1
× COUT × ESRCOUT
Where COUT is the output capacitor, RL is load resis-
tance;
ESRCOUT is the equivalent series resistance of output
capacitor.
The compensation design is to shape the converter close
loop transfer function to get desired gain and phase. For
most cases, a series capacitor and resistor network con-
nected to the COMP pin sets the pole-zero and is ad-
equate for a stable high-bandwidth control loop.
In the AME5283, FB pin and COMP pin are the invert-
ing input and the output of internal transconductance er-
ror amplifier (EA). A series RC and CC compensation
network connected to COMP pin provides one pole and
one zero: for RC << AEA/GEA
fP2
=
2π
×CC
× RC +
1
AEA
GEA

≈
2π
GEA
×CC ×
AEA
fZ2
=
2π
1
×CC
×
RC
Rev. A.03
Where GEA is the error amplifier transconductance
AEA is the error amplifier voltage gain
RC is the compensation resistor
CC is the compensation capacitor
The desired crossover frequency fC of the system is
defined to be the frequency where the control loop has
unity gain. It is also called the bandwidth of the con-
verter. In general, a higher bandwidth means faster re-
sponse to load transient. However, the bandwidth should
not be too high because of system stability concern. When
designing the compensation loop, converter stability un-
der all line and load condition must be considered. Usu-
ally, it is recommended to set the bandwidth to be less
than 1/10 of switching frequency. Using selected cross-
over frequency, fC, to calculate RC:
RC
=
fC
×
VOUT
VFB
× 2π × COUT
GEA × GCS
Where GCS is the current sense circuit
transconductance. The compensation capacitor CC and
resistor RC together make zero. This zero is put some-
where close to the pole fP1 of selected frequency. CC is
selected by:
CC
=
COUT × RL
RC
Checking Transient Response
The regulator loop response can be checked by look-
ing at the load transient response. Switching regulators
take several cycles to respond to a step in load current.
When a load step occurs, VOUT immediately shifts by an
amount equal to (∆ILOAD x ESR), where ESR is the effec-
tive series resistance of COUT. ∆ILOAD also begins to charge
or discharge COUT, which generates a feedback error sig-
nal.
The regulator loop then acts to return VOUT to its steady
state value. During this recovery time VOUT can be moni-
tored for overshoot or ringing that would indicate a stabil-
ity problem.
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