AD8005ARZ Datasheet, PDF (5/12 Pages) Analog Devices – 270 MHz, 400 μA Current Feedback Amplifier

5
4
V_S = ؎5V
3
V_OUT = 200mV p-p
R_L = 1k⍀
2
G = +1
1
0
–1
G = +2
–2
G = +10
R_F = 499⍀
–3
–4
–5
1
10
100
500
FREQUENCY – MHz
Figure 4. Frequency Response; G = +1, +2, +10; V_S = ±5 V
Typical Characteristics–AD8005
5
4
V_S = ؎5V
V_OUT = 200mV p-p
3
R_L = 1k⍀
2
1
0
–1
G = –1
R_F = 1.5k⍀
–2
G = –10
–3
R_F = 1k⍀
–4
–5
1
10
100
500
FREQUENCY – MHz
Figure 7. Frequency Response; G = –1, –10; V_S = ±5 V
6.2
6.1
6.0
5.9
5.8
G = +2
5.7
V_OUT = 200mV p-p
5.6
R_L = 1k⍀
5.5
5.4
5.3
5.2
0.1
1
10
100
500
FREQUENCY – MHz
Figure 5. Gain Flatness; G = +2; V_S = ±5 V or +5 V
140
0
120
–40
PHASE
100
–80
80
–120
GAIN
60
–160
40
–200
20
–240
0
–280
1k
10k
100k
1M
10M
100M
1G
FREQUENCY – Hz
Figure 8. Transimpedance Gain and Phase vs. Frequency
7
6
5
4
V_S = ؎5V
V_S = ؎5V
V_OUT = 2V p-p
3
V_OUT = 4V p-p
2
1
0
–1
–2
1
10
100
500
FREQUENCY – MHz
Figure 6. Large Signal Frequency Response;
G = +2, R_L = 1 kΩ
10
9
8
7
6
V_S = +5V
5
G = +2
4
R_L = 1k⍀
3
2
1
0
0.5 1
10
100
FREQUENCY – MHz
Figure 9. Output Swing vs. Frequency; V_S = ±5 V
REV. A
–5–